All categories

3 years ago

43ones x3 tens=how many tens

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

7 0

There are 129 tens because 43x30 (3 tens) is 1,290

You might be interested in

Which of these statements is true for f(x)=3*2? A. It is always decreasing. B. The y-intercept I (0,1). C. The domain is x >0

IceJOKER [234]

none

are you sure that is the right equation

4 0

3 years ago

Read 2 more answers

PLLLZZZZZ HEEEEELLLLPPPPPPP

IceJOKER [234]

The answer should be C.

4 0

3 years ago

Read 2 more answers

Help me, please and ty

Ira Lisetskai [31]

Answer:

3/5, 30%, 0.1

Step-by-step explanation:

0.4 + 1/2 + 40% = 0.4 + 0.5 + 0.4 = 1.3

3/4 + 0.25 + 1/2 = 0.75 + 0.25 + 0.5 = 1.5

3/5 + 30% + 0.1 = 0.6 + 0.3 + 0.1 = 1

The last choice is a probability complement because all values add to 1.

8 0

3 years ago

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago

D. 360 DCW Help please !!! My answer is C not Sure

tino4ka555 [31]

Flipping something 180 degrees (doesn't matter if clockwise or counterclockwise) will always flip that thing upside down.

Your answer is 180 degrees.

Now, the reason why it's not 270 degrees clockwise because that's pretty much turning that 90 degrees counterclockwise. And 90 degrees is about how much a car does when making a left or right turn.

Have an awesome day! :)

7 0

3 years ago