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Vsevolod [243]
3 years ago
14

How do you find the vertex and the axis of symmetry of the equation? y = 2x^2 + 28x - 10

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0

Answer:

-7±3√6

Step-by-step explanation:

Digiron [165]3 years ago
5 0

Answer:

By completing the square and rewrite equation in the form of

y = a{(x   -  p)}^{2}  + q

Where the vertex is (p, q)

axis of symmetry is x=p

Step-by-step explanation:

The solution is in the picture

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Write the equation of the line passing through points (2,-2) and (1,0) in slope intercept form.
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Step-by-step explanation:

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What would be the surface area of the figure..
valina [46]

Answer:

<h2>           503 cm²</h2>

Step-by-step explanation:

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8 0
3 years ago
The function h is defined as follows.
JulsSmile [24]

Answer:

The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.

y = a(x-h)2 + k            standard form

y = 5x2 - 4                  original equation

y = 5(x-0)2 - 4            re-written in standard form

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Four (4) units up is k + 4--->-4 + 4 = 0.

Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.

Step-by-step explanation:

hope this helps

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