How do you find the vertex and the axis of symmetry of the equation? y = 2x^2 + 28x - 10
2 answers:
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We are given degree of the polynomial function = 3.
Because degree is 3, there should be three x-intercepts of the given graph of the polynomial.
We also given roots of the equation f(x)=0 are −2 , 0, and 3.
Therefore, x intercepts should be at:
(0,0), (-2,0) and (3,0).
<h3>In the given options third option shows x-intercepts at 0, -2 and 3.</h3><h3>Therefore, correct option is 3rd option.</h3>
