Question

How do you find the vertex and the axis of symmetry of the equation? y = 2x^2 + 28x - 10

Answer 1

Answer:

-7±3√6

Step-by-step explanation:

Answer 2

Answer:

By completing the square and rewrite equation in the form of

$y = a{(x - p)}^{2} + q$

Where the vertex is (p, q)

axis of symmetry is x=p

Step-by-step explanation:

The solution is in the picture