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IceJOKER [234]
3 years ago
15

Which situations describe an elastic collision?

Physics
1 answer:
bija089 [108]3 years ago
8 0

Answer: Two glass marbles bounce off each other.

Explanation:Elastic collisions are collisions in which both momentum and kinetic energy are conserved. The total system kinetic energy before the collision equals the total system kinetic energy after the collision. If total kinetic energy is not conserved, then the collision is referred to as an inelastic collision.

An elastic collision occurs when the two objects "bounce" apart when they collide. Two rubber balls are a good example. In an elastic collision, both momentum and kinetic energy are conserved. Almost no energy is lost to sound, heat, or deformation.

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may i ask your answer soloutions... and i believe that the correct answer is mass


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3 years ago
A light source radiates 60.0 W of single-wavelength sinusoidal light uniformly in all directions. What is the average intensity
umka21 [38]

Answer: 29.85\ W/m^2

Explanation:

Given

Power P=60\ W

Distance from the light source r=0.4\ m

Intensity is given by

I=\dfrac{P}{4\pi r^2}

Inserting values

\Rightarrow I=\dfrac{60}{4\pi (0.4)^2}\\\\\Rightarrow I=\dfrac{60}{2.010}\\\\\Rightarrow I=29.85\ W/m^2

3 0
3 years ago
Read 2 more answers
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

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Homestasis is the word .
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A is the only logical answer
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