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<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

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t₃= 30 s

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Total distance

Solution

State 1 : acceleration

$\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m$

$\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s$

State 2 : constant speed

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State 3 : deceleration

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Total distance : state 1+ state 2+state 3

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