All categories

2 years ago

The current through a stationary loop in a constant magnetic field:

Physics

1 answer:

Angelina_Jolie [31]2 years ago

7 0

Answer:

remains zero

Explanation:

According to the Faraday's law of electromagnetic induction, when the magnetic flux linked with the coil changes, an induced emf is developed in the coil.

Here the loop is kept stationary in a constant magnetic field, so no magnetic flux linked with the coil changes, hence the current remains zero in the coil.

You might be interested in

In which situation is the acceleration of the car negative?

VikaD [51]

When a car is slowing down, it has a negative acceleration. Although it is not going a negative speed, it is decreasing in velocity, which is the definition of a negative acceleration.

Hope this helps!

4 0

2 years ago

Read 2 more answers

Help<br><br> Why does the sun move around the Milky Way galaxy

AnnyKZ [126]

It doesn't the sun stays still we move around the sun

5 0

2 years ago

Read 2 more answers

31. If you threw a baseball straight out at 45 m/s from a height of 1.5 meters (A) how long would it be in the air? B) How far o

coldgirl [10]

Answer:

A) t = 0.55 s

B) x = 24.8 m

Explanation:

A) We can find the time at which the ball will be in the air using the following equation:

$y_{f} = y_{0} + v_{0y}t - \frac{1}{2}gt^{2}$

Where:

$y_{f}$ is the final height= 0

$y_{0}$ is the initial height= 1.5 m

$v_{0y}$ is the component of the initial speed in the vertical direction = 0 m/s

t: is the time =?

g: is the gravity = 9.81 m/s²

$0 = 1.5 m - \frac{1}{2}9.81 m/s^{2}t^{2}$

By solving the above equation for t we have:

$t = \sqrt{\frac{2*1.5 m}{9.81 m/s^{2}}} = 0.55 s$

Hence, the ball will stay 0.55 seconds in the air.

B) We can find the distance traveled by the ball as follows:

$x_{f} = x_{0} + v_{0x}t + \frac{1}{2}at^{2}$

Where:

a: is the acceleration in the horizontal direction = 0

$x_{f}$ is the final position =?

$x_{0}$ is the initial position = 0

$v_{0x}$ is the component of the initial speed in the horizontal direction = 45 m/s

$x_{f} = x_{0} + v_{0x}t + \frac{1}{2}at^{2}$

$x_{f} = 0 + 45 m/s*0.55 s + 0 = 24.8 m$

Therefore, the ball will travel 24.8 meters.

I hope it helps you!

3 0

2 years ago

Mutations can be transmitted to the next generation only if they are present in

emmainna [20.7K]

Answer:

The germline (the gametes)

Explanation:

Mutations are permanent changes in the DNA sequence. They can occur randomly, from mistakes during DNA replication, or as the result of external factors like UV radiation.

For these mutations to be passed on to the next generation, they must be present in the DNA of the gametes(i.e. the egg and sperm cells). This is because this is the DNA that goes on to make the offspring in the next generation following fertilisation.

If mutations are present in somatic cells (i.e. cells other than the gametes), they are not passed on to the next generation. For example, if someone gets mutations in their skin cells as a result of exposure to UV rays, this will not be passed on to their children.

7 0

2 years ago

Someone drops a brick on a 2.6 kg cart moving at 28.2 cm/s. After the collision, the dropped brick and cart are moving together

Softa [21]

Answer:

2.087 kg

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision.

MU + mu = V(M+m)............................ Equation 1

Where M = mass of the cart, m = mass of the brick, U = initial velocity of the cart, u = initial velocity of the brick, V = velocity of both cart and brick after collision.

Note: The initial velocity of the brick is zero Thus mu = 0

making m the subject of the equation,

m =(MU/V)-M ........................................ Equation 2

Given: M = 2.6 kg, U = 28.2 cm/s = 0.283 m/s, V = 15.7 cm/s = 0.157 m/s.

Substituting into equation 2,

m = (2.6×0.283/0.157)-2.6

m = 2.087 kg

Thus the mass of the brick = 2.087 kg

5 0

2 years ago