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4 years ago

Find the missing sides for angle ABC below. AND the solve for the area of angle ABC

Mathematics

1 answer:

Vinvika [58]4 years ago

6 0

There is a 45,45,90 triangle and a 30,60,90 triangle within triangle ABC.

So you can just use the relationships between sides in these special triangles to find the desired lengths.

AB=3√2

z=3

b=3 (It is isosceles so we know that b=z)

With b=3, we know that...

x=3·2=6

y=3√3

answers: z=3,b=3,x=6,y=3√3

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What is the value of x to the nearest tenth? 3.1 4.8 5.4 3.5

Tanya [424]

Answer:

5.4

Step-by-step explanation:

I am not really sure about this type of problem, but a diameter has to cross the midpoint of the circle the dark dot and hit two point on both side of the circle. Yet the line 9.6 is not a diameter since it didn't go through the center, so the diameter has to be longer than 9.6. But x is looking for radius. so divide 9.6 by 2 u get 4.8 but that is not a diameter and the real diameter is longer that mean the radius is longer so the only answer is 5.4

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4 years ago

a classroom has triangular tables there is enough space at each side of a table to seat one child the tables in this class are a

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Answer:

Step-by-step explanation:

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3 years ago

Leigh has a piece of rope that is 6 2/3 feet long. How do you write 6 2/3 as a fraction greater than 1

aleksley [76]

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3 years ago

Read 2 more answers

Solve photo question. Mathematics. Please.

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4 years ago

What are the values of m and n in the matrix addition below?

Aleksandr [31]

ANSWER

The correct answer is $m=45,n=12$ .

EXPLANATION

We were given the matrix equation;

$\left[\begin{array}{cc}n-1&6\\-19&m+3\end{array}\right] +\left[\begin{array}{cc}-1&0\\16&-8\end{array}\right] =\left[\begin{array}{cc}10&6\\-3&40\end{array}\right]$ .

We must first simplify the Left Hand Side of the equation by adding corresponding entries.

$\left[\begin{array}{cc}n-1+-1&6+0\\-19+16&m+3-8\end{array}\right]=\left[\begin{array}{cc}10&6\\-3&40\end{array}\right]$ .

That is;

$\left[\begin{array}{cc}n-2&6\\-3&m-5\end{array}\right]=\left[\begin{array}{cc}10&6\\-3&40\end{array}\right]$ .

Since the two matrices are equal, their corresponding entries are also equal. we equate corresponding entries and solve for m and n.

This implies that;

$n-2=10$

We got this equation from row one-column one entry of both matrices.

$n=12$

Also, the row three-column three entries of both matrices will give us the equation;

$m-5=40$

$m=45$

Hence the correct answer is $m=45,n=12$ .

The correct option is option 2

6 0

3 years ago