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Zolol [24]
3 years ago
11

Please help!!

Mathematics
1 answer:
postnew [5]3 years ago
8 0

2  \frac{5}{8}  \div 2  \frac{1}{2}
Change the mixed fractions to improper fractions.
To do this, multiply the whole number part by the denominator. Add that to the numerator. Then write the result on top of the denominator.

You would now have:
\frac{21}{8}  \div  \frac{5}{2}
Change the division sign to a multiplication sign by turning the second fraction upside down.
That is,
\frac{21}{8}  \times  \frac{2}{5}

The answer is:
\frac{42}{40}

This can be simplified to:
\frac{21}{20}



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A population of values has a normal distribution with μ = 155.4 and σ = 49.5 . You intend to draw a random sample of size n = 24
xz_007 [3.2K]

Answer:

(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.

(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.

Step-by-step explanation:

Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.

(a)

Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

P(158.6 < X

*Use a standard normal table.

Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.

(b)

A sample of <em>n</em> = 246 is selected.

Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

P(158.6 < \bar X

*Use a standard normal table.

Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.

4 0
3 years ago
Read 2 more answers
15. (NO CALCULATOR) A restaurant took 1/3 of an hour to use 1/5 of a
kotykmax [81]

Answer:

It would take 5/3 or 1 2/3 hours to use a package of napkins.

Step-by-step explanation:

1/3=1/5

2/3=2/5

3/3=3/5

4/3=4/5

5/3=5/5

5/3= 1 2/3

8 0
3 years ago
Easy multiple choice!
Zepler [3.9K]

Answer:

-4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

4x + 5y = -12

-2x + 3y = -16

<u>Step 2: Rewrite Systems</u>

-2x + 3y = -16

  1. Multiply everything by 2:                    -4x + 6y = -32

<u>Step 3: Redefine Systems</u>

4x + 5y = -12

-4x + 6y = -32

<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                    11y = -44
  2. Divide 17 on both sides:                  y = -4
5 0
3 years ago
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Mary brought $20 to the skating rink. She paid $5.50 admission and $3.75 to rent skates. She also purchased two bottles of water
Salsk061 [2.6K]

Answer:

20-14.5=5.5

Step-by-step explanation:

7 0
3 years ago
Anyone please help me pleaseeee
lora16 [44]

R = { (x,y): 3x-y=0 }

The condition is 3x=y so that's not going to be any of these things.

R is reflexive if (x,x)∈R for all x.   Let's check.

3x - y = 3x - x = 2x ≠ 0  necessarily.   NOT REFLEXIVE

R is symmetric if (x,y)∈R → (y,x)∈R.   Let's check.

(x,y)∈R  so

3x-y = 0

y  = 3x

Is  (y,x)∈R.  That would be true if 3y-x=0

3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC

R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R.   Let's check.

3x-y = 0  so y=3x

3y-z = 0 so z=3y = 9x

3x - z = 3x - 9x = -6x ≠ 0 necessarily   NOT TRANSITIVE

6 0
3 years ago
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