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iren [92.7K]
4 years ago
10

Fluorescent light bulbs have lifetimes that follow a normal distribution, with an average life of 1,685 days and a standard devi

ation of 1,356 hours. In the production process the manufacturer draws random samples of 197 light bulbs and determines the mean lifetime of the sample. What is the standard deviation of the sampling distribution of this sample mean?
Mathematics
1 answer:
bearhunter [10]4 years ago
6 0

Answer:

3,238

Step-by-step explanation:

1,685+1,356+197=3,238

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The Miami airport offers several different parking options for visitors. A new short term
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Answer:

  (0, 24]

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The horizontal extent of the graph is from 0 to 24. There is an open circle at x=0, and a closed circle at x=24. Hence, the domain of the function is ...

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In interval notation, this is

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We note that this is not one of your answer choices. You may want to discuss this with your teacher.

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4 years ago
HELP PLEASE!! I NEED HELP ASAP!
Alex73 [517]

Answer:

4. A

5. B

Step-by-step explanation:

4. I'll solve question four first:

The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.

5--3/2--2 or 8/4;simplified to 2/1 or 2.

Now use point-slope form: y-y1 = m(x-x1)

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5. Do the same for question 5.

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7 0
3 years ago
A dashboard warning light is supposed to flash red if a car’s oil pressure is too low. On a certain model, the probability of th
PilotLPTM [1.2K]

Answer:

0.8462 or 84.62%

Step-by-step explanation:

The probability that the light flashes is given by the probability of it flashing when it should added to the probability of flashing when it should not:

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The probability that the oil pressure is low (driver needs to be concerned) is given by the probability that oil is low and the light flashes divided by the probability that the light flashes.

P(O|F) =\frac{P(O_F)*P(O)}{P(F)} \\P(O|F) =\frac{0.99*0.10}{0.117}\\ P(O|F) =0.8462

When the warning light goes on, there is a 0.8462 probability that the oil pressure is low.

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