check the picture below.
since we know all those interior points are midpoints, then those interior lines are midsegments, recall the midsegment is half the parallel base.
in this case, the green DF || AC, and since AC is 50, DF is half that, 50/2.
Answer:
(0, 24]
Step-by-step explanation:
The horizontal extent of the graph is from 0 to 24. There is an open circle at x=0, and a closed circle at x=24. Hence, the domain of the function is ...
0 < x ≤ 24
In interval notation, this is
(0, 24]
__
We note that this is not one of your answer choices. You may want to discuss this with your teacher.
Answer:
4. A
5. B
Step-by-step explanation:
4. I'll solve question four first:
The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.
5--3/2--2 or 8/4;simplified to 2/1 or 2.
Now use point-slope form: y-y1 = m(x-x1)
y--3 = 2(x--2): Substitute in the values of y1, m, and x1.
y+3 = 2x + 4: Distribute.
y = 2x + 1: Subtract three from both sides.
5. Do the same for question 5.
The first point is (-4, 2), the second point is (4, -1).
-1-2/4--4; -3/8.
Now use point-slope form:
y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.
y = -3/8x + 1/2
Answer:
0.8462 or 84.62%
Step-by-step explanation:
The probability that the light flashes is given by the probability of it flashing when it should added to the probability of flashing when it should not:

The probability that the oil pressure is low (driver needs to be concerned) is given by the probability that oil is low and the light flashes divided by the probability that the light flashes.

When the warning light goes on, there is a 0.8462 probability that the oil pressure is low.