What is the slope of a line parallel to -2x + 5y =8

motikmotik

Simplify the fractions if not in lowest terms.Multiply the numerators of the fractions to get the new numerator.Multiply the denominators of the fractions to get the new denominator.

8 0

3 years ago

On a map, the distance between Greenville and Fairview is 7 1/4 inches. If the map uses a scale of 1/2 inch = 40 miles, what is

lubasha [3.4K]

The actual distance between cities is 580 miles.

Step-by-step explanation:

Map distance = $7\frac{1}{4}$ inches = $\frac{29}{4}\ inches$

Scale used;

$\frac{1}{2}\ inches = 40\ miles$

Multiplying both sides by 2

$2*\frac{1}{2}=40*2\\1\ inch = 80\ miles\\$

Now,

$\frac{29}{4}\ inches = \frac{29}{4}*80\\\\\frac{29}{4}=29*20\\\\\frac{29}{4}\ inches = 580\ miles$

The actual distance between cities is 580 miles.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

4 0

3 years ago

The number part when a number and a variable are multiplied together in a term is called the _____.

77julia77 [94]

Answer:

Coefficient

Step-by-step explanation:

-Usually a combination of variables and constants are multiplied to get a product.

-The constant or number part in the multiplication process is called the Coefficient

7 0

3 years ago

Alexandra has 78 emails in her box. she deletes 47 emails. How many emails are left in her box? Draw jumps and label the number

labwork [276]

There are 31 emails left in her box. Hope this helps!! :)

7 0

3 years ago

Read 2 more answers

work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company deci

Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the conference is 0.10.

(c) The probability that Clarice attends the conference is 0.40.

(d) The probability that John stays home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (M), Roberto (R), John (J), Dominique (D) and Clarice (C) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

${5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10$

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event E is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of Roberto and John is, RJ.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the conference as follows:

$P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10$

Thus, the probability that Roberto and John attend the conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the conference as follows:

$P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40$

Thus, the probability that Clarice attends the conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays home as follows:

$P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60$

Thus, the probability that John stays home is 0.60.

4 0

3 years ago