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andreyandreev [35.5K]
3 years ago
10

Help please!!!!!!!!!

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

B. x^{2} - 4x - 5

Step-by-step explanation:

(p о n) (x) is the same thing as (p(n(x))

We know n(x) = x - 5, so let's input that into our expression

(p(x - 5))

Since we know p(x) = x^2 + 6x, let's replace the x with the new value x-5. Now our expression is:

p(x) = (x - 5)^2 + 6(x - 5)

Now all we have to do is simplify.

(x - 5)^2 is the same as:  (x - 5)(x - 5)

Using the foil method, it simplifies to:  x^2 - 10x + 25

6 (x - 5) = 6x - 30

Now our expression is:  x^2 - 10x + 25 + 6x - 30

Combine like terms:  x^2 - 4x - 5

The expression is: x^{2} - 4x - 5

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PLEASE HELP!!!!! What is the value of x in the matrix equation below?
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The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right]  =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Matrix equality gives,

1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2

Solving the equations together,

y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10

We can see that the equations are not consistent.

There is no solution.

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3 years ago
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