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3 years ago

What is the graph for y=3x+13 and y=x-3

1 answer:

defon3 years ago

3 0

In a question like this, you want to approach it with the equation "slope intercept form" which is $y=mx+b$
b = y-intercept
- the point where the line intercepts the y-axis
m = slope

I suggest using Desmos Graphing Calculator, it really helps and shows you a graphed equation. Let me know what you get!

You might be interested in

What is an equation of the line that passes through the point (2, 4 and is perpendicular to the line whose equation is 3y = 6x 3

Maru [420]

Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,

m1*m2=-1

So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...

3y=6x ?3 (not sure what you wanted to type there)

anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.

So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:

y=-x/2 +b, we can now you the point given to solve for b

4=-2/2 +b

4=-1+b

b=5 so

y=-x/2 +5 or more neatly

y=(10-x)/2

3 0

3 years ago

Can anyone help me please

kicyunya [14]

Answer:

yes wait im doing it. do I put them un order

3 0

3 years ago

What do you know to be true about the values of p and q?

ss7ja [257]

Answer:

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°, thus

p = 180° - (80 + 20)° = 180° - 100° = 80° and

q = 180° - (45 + 55)° = 180° - 100° = 80°

Thus p = q → B

7 0

3 years ago

Find all critical points of the given plane autonomous system. (Enter your answers as a comma-separated list.) x′ = x 12 − x − 1

Andru [333]

Answer:

the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

Step-by-step explanation:

To consider the autonomous system

$x' =x (12 -x - \dfrac{1}{2})$

$y' = y( 20 -y - x)$

The critical points of the above system can be derived by replacing x' = o and y' = 0.

i.e.

$x' =x (12 -x - \dfrac{y}{2}) = 0$

$\dfrac{x}{2} (24 -2x - y) = 0$

x = 0 or 24 - 2x - y = 0 ----- (1)

Also

$y' = y( 20-y-x) = 0$

y( 20 -y - x) = 0

y = 0 or 20 - y - x = 0 ----- (2)

By solving (1) and (2);

we get x = 4 and y = 16

Suppose x = 0 from (2)

y = 20

Also;

if y = 0 from (1)

x = 12

Thus, the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

6 0

2 years ago

Over the last three evenings, Diane received a total of 105 phone calls at the call center. The third evening, she received 4 ti

sergij07 [2.7K]

Answer:

Make an eqaution from here.
Let’s make evening 2 “x”

So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).

X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x

And when solved, it has to equal 105.

So solve from here.
Combine like terms.

6x-9=105
Isolate

6x=114
x= 19

First evening is 9 less then 19, so 10.

The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76

1st night = 10

2nd night= 19 calls
Thrid night= 76 calls

8 0

2 years ago