HEY THERE!!
For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1) .
This means that the angular quantum number for a principal quantum number of 2 is equivalent to:
l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1
So the answer is 0, 1
HOPE IT HELPED YOU.
i think it’s D , not sure though
Answer:
Some of the properties of cobalt silicate include:
It occurs as a crystal with red- violet type colour.
The shape of the cobalt silicate crystal is orthorhombic.
The molecular weight of cobalt silicate is 209.95.
The melting temperature of Cobalt Silicate is 1618 degrees Celsius.
The density of Cobalt Silicate is 4.63 grams per centimetre cube.
Cobalt Silicate can serve as a semi-conductor.