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Zinaida [17]
3 years ago
9

In order for a hypothesis to become a theory, scientists MUST _____. A. do many experiments B. find a well-defined question C. m

ake their question testable D. throw out their earlier experimental results
Chemistry
2 answers:
Dovator [93]3 years ago
8 0

the answer is A do many experiments.

Tamiku [17]3 years ago
7 0
A. If there is enough evidence to support a hypothesis it becomes a theory. In order to get evidence a scientist would have to perform many experiments.
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How many moles of SnCl2 will be produced if 85.3 g of FeCl3 is reacted with an excess of Sn for the following reaction:2 FeCl3(s
Ronch [10]

Answer:

The answer to your question is 0.79 moles of SnCl₂  

Explanation:

Data

moles of SnCl₂ = ?

mass of FeCl₃ = 85.3 g

excess Sn

Balanced chemical reaction

                 2 FeCl₃  +  3 Sn  ⇒   3 SnCl₂  +  2 Fe

Process

1.- Convert the mass of FeCl₃ to moles

Molar mass of FeCl₃ = 56 + (35.5 x 3)

                                  = 56 + 106.5

                                  = 162.5 g

Use proportions to find the moles of FeCl₃

                       162.5 g -------------------- 1 mol

                         85.3 g -------------------  x

                         x = (85.3 x 1) / 162.5

                         x = 0.525 moles

2.- Find the number of moles SnCl₂

                     2 moles of FeCl₃ ----------------- 3 moles of SnCl₂

                     0.525 moles        ----------------- x

                     x = (0.525 x 3) / 2

                    x = 0.79 moles of SnCl₂                  

4 0
4 years ago
I'M GIVING 50 POINTS!!!!! NEEDS TO BE CORRECT EXPLAIN!!!!!!!!!
Virty [35]
There are 3 types of atoms in an ammonia solution, NH4OH: nitrogen, hydrogen and oxygen. So, your answer in this context is A.
However, if you were considering just ammonia on its own (NH3) there are only two types of atoms, nitrogen and hydrogen.
8 0
3 years ago
Read 2 more answers
Which of the following item(s) explain the differences between the Ka values. Choose one or more: A. The oxidation state for oxy
Allisa [31]

Answer:

<em>C. The electron-withdrawing fluorine atoms pull electron density from the oxygen in trifluoroacetate. The negative charge is more stabilized in trifluoroacetate by this effect.</em>

<em></em>

Explanation:

<em>The structures of trifluoroacetate and acetic acid are both shown in the image attached.</em>

<em>The trifluoroacetate anion (CF3CO2-), just like the acetate anion has in the middle, two oxygen atoms.</em>

<em>However, in the trifluoroacetate anion, there are also three electronegative fluorine atoms attached to the nearby carbon atom attached to the carbonyl, and these pull some electron density through the sigma bonding network away from the oxygen atoms, thereby spreading out the negative charge further. This effect, called the "inductive effect" stabilizes the anion formed,the trifouoroacetate anion is thus more stabilized than the acetate anion.</em>

<em>Hence, trifluoroacetic acid is a stronger acid than acetic acid, having a pKa of -0.18.</em>

<em></em>

<u><em>Hope this helps!</em></u>

<u><em>Please mark brainliest!</em></u>

3 0
3 years ago
What is common about the elements of a period? Select all that apply. They have the same number of electron energy levels. They
Ann [662]

Answer:

They have the same number of electron energy levels.

They transition from a metal to noble gas.

Explanation:

Periods in the periodic table of elements refer to elements in the same row. All the elements in a certain row of the periodic table;

have the same number of electron energy levels.

transition from a metal to noble gas.

4 0
3 years ago
What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?
ArbitrLikvidat [17]
Data:

m (<span>Sample Mass) = ? 
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (Hg_{2}  Cl_{2})
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass Hg_{2} Cl_{2} = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

n =  \frac{m}{MM}

Solving:


n = \frac{m}{MM}
0.714 =  \frac{m}{472.09}
m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark

Answer:
By approximation would be letter D) <span>337.2 g</span>


8 0
3 years ago
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