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Effectus [21]
3 years ago
12

As a child (with a mass of 35.0 kg) you take your 5.0-kg sled to Orchard Downs. If you are sliding down the hill on your sled, w

ith a kinetic energy of 260 J, how fast are you moving?
Chemistry
1 answer:
alukav5142 [94]3 years ago
3 0

Velocity = 3.61 m/s

<h3>Further explanation</h3>

Given

mass of child = 35 kg

mass of sled = 5 kg

Kinetic energy = 260 J

Required

velocity

Solution

Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

KE = 1/2.mv²

mass of object :

= mass child + mass sled

= 35 kg + 5 kg

= 40 kg

Input the value :

v²=KE : 1/2.m

v²= 260 : 1/2.40 kg

v²=13

v=3.61 m/s

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Why do you think the soccer ball fell more slowly than the golf ball
alexgriva [62]

Answer:

kinetic energy than the potential energy it carries

Explanation:

3 0
3 years ago
What is the ph of 0.1 m naoh solution??
Rudik [331]
NaOH is a strong base so pH will be around 13 to 12. Whatever number of moles of NaOH you have approximately the pH of NaOH will be around 14 13 or 12  
7 0
3 years ago
1 Calcium carbonate breaks down on heating to produce calcium oxide and carbon dioxide gas.
Alborosie

Answer:  See below

Explanation:

1.  a)  0.15 moles calcium carbonate  (15g/100g/mole)

   b)  0.15 moles CaO  (molar ratio of CaO to CaCO3 is 1:1)

   c)   8.4 grams CaO  (0.15 moles)*(56 grams/mole)

2. a)  0.274 moles Na2O  (17g/62 grams/mole)

   b)  46.6 grams NaNO3  (2 moles NaNO3/1 mole Na2O)*(0.274 moles Na2O)*(85 g/mole NaNO3)

7 0
2 years ago
A balloon is filled with 0.400 moles of gas. How many liters of gas at STP were pumped into the balloon?
Fynjy0 [20]

Answer:

8.96 L

Explanation:

At STP, 1 mole = 22.4 L

0.400 mole *   (22.4 L. /1 mole of gas) = 8.96 L

3 0
3 years ago
A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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