Answer:

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel
And the anfle is approximately 
Step-by-step explanation:
For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.
a=[1,2,-2], b=[4,0,-3,]
The dot product on this case is:

Since the dot product is not equal to zero then the two vectors are not orthogonal.
Now we can calculate the magnitude of each vector like this:


And finally we can calculate the angle between the vectors like this:

And the angle is given by:

If we replace we got:

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel
And the anfle is approximately 
Answer:
x = 1 y = -4
Step-by-step explanation:
- Plug the value of y into the other equation.
x + 3y = -11
x + 3(-4x) = -11
x - 12x = -11
-11x = -11
x = 1
- Now substitute the value of x into any equation.
y = -4x
y = -4(1)
y = -4
(4x−101)(2x+3)
Apply the distributive property by multiplying each term of 4x−101 by each term of 2x+3.
8x²+12x−202x−303
Combine 12x and −202x.
8x²−190x−303
Answer:
all real numbers
Step-by-step explanation:
The graphs of positive and negative x^2 parabolas will always have a domain of all real numbers. Even though you only have a portion of the graph and see a "restriction" on your domain values, it is incorrect to assume that the domain is limited to what you can see. As the branches of the parabola keep going up and up and up, the values of x keep getting bigger and bigger and bigger. Again, this is true for all + or - parabolas. ....... Can consider brainlist*:)