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Fofino [41]
3 years ago
7

If two thirds of a number decreased by 20 is 40, what is the number

Mathematics
1 answer:
oee [108]3 years ago
8 0

Answer:

The unknown number is 90

Step-by-step explanation:

This question requires a good understanding so as to interprets it well

And always ensure that all symbols used in representation are well stated so as to help the examiner or anyone who will mark it to understand better

So back to the question,let the unknown number be x

And two thirds of the unknown number is 2/3x

2/3x was decreased by 20 which can be written as 2/3x-20

And this decrease gives 40

That's,2/3x-20=40

Then go ahead to solve the question

Start by finding the LCM and the LCM is 3

2x-60/3=40

Cross multiply

2x-60=40×3

2x-60=120

Collect like terms by adding 60 to both sides

2x=180

Divide both sides by 2

x=90

Therefore the final answer is 90

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80

Step-by-step explanation:

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Five more than the product of a number and 8 is equal to 6.
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3 years ago
7. In a state lottery, a player must choose 8 of the numbers from 1 to 40. The lottery commission then performs an experiment th
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Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8

b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4

Step-by-step explanation:

Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40

a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8

There are one in hundred million chances that the draw numbers are precisely the chosen ones.

b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)

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P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.

There are approximately 300,000 chances that 7 of the players numbers are chosen

c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.

P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]

P(at least 6 players numbers are drawn) = 1.84×10^-4.

There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.

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