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3 years ago

My new speakers were $155 but I also had to pay the 6% tax what did I pay for my new speakers

Mathematics

1 answer:

elena-s [515]3 years ago

6 0

Answer:

164.30

Step-by-step explanation:

just find 106 percent of 155

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Write 225,120,000 in scientific notation

ivolga24 [154]

2.2512*10^8 let me know if its wrong

4 0

3 years ago

Add the following Linear Expressions.<br> (-6y - 3) + 5 (3+2.5y)

amm1812

Answer= 6.5y+12

distribute the 5 in the parentheses:
(-6y-3) + (15+12.5y)
(you can take away the parentheses after this step)

then add like terms together.
12.5y + (-6y) = 6.5y
15 + (-3) = 12

make it one expression.
6.5y + 12

4 0

3 years ago

Is 0.032 a terminating decimal

svp [43]

I don’t think it is, sorry I’m not 100% sure, good luck though

3 0

3 years ago

If d , e, and f are midpoints of the sides of ABC, find the perimeter of ABC.

ehidna [41]

Answer:

Perimeter of the ΔDEF = 10.6 cm

Step-by-step explanation:

The given question is incomplete; here is the complete question with attachment enclosed with the answer.

D, E, and F are the midpoints of the sides AB, BC, and CA respectively. If AB = 8 cm, BC = 7.2 cm and AC = 6 cm, then find the perimeter of ΔDEF.

By the midpoint theorem of the triangle,

Since D, E, F are the midpoints of the sides AB, BC and CA respectively.

Therefore, DF ║ BC and $FD=\frac{1}{2}\times(BC)$

FD = $\frac{7.2}{2}$

= 3.6

Similarly, $FE=\frac{1}{2}\times(AB)$

$FE=\frac{8}{2}$

FE = 4 cm

And $DE=\frac{AC}{2}$

DE = $\frac{6}{2}$

= 3 cm

Now perimeter of ΔDEF = DE + EF + FD

= 3 + 4+ 3.6

= 10.6 cm

Perimeter of the ΔDEF is 10.6 cm.

7 0

3 years ago

Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL

scoray [572]

Answer:

$8(x^2+y^2)-4x-30y+23=0$

Step-by-step explanation:

<u />

<u>Distance formula</u>

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let P(x, y) = any point on the locus

Let A = (0, 2)

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

$PA=\dfrac{1}{3}PB$

Therefore, using the distance formula:

$\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}$

Square both sides:

$\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]$

$\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)$

Multiply both sides by 9:

$\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9$

$\implies 8x^2+8y^2-4x-30y+23=0$

$\implies 8(x^2+y^2)-4x-30y+23=0$

3 0

2 years ago

My new speakers were $155 but I also had to pay the 6% tax what did I pay for my new speakers​

My new speakers were $155 but I also had to pay the 6% tax what did I pay for my new speakers