Formulas tab > in the Function Library group, click Lookup & Reference button, select VLOOKUP. Type A3 in the Lookup_value argument box. Type Abbreviation in the Table_array argument box. Type 2 in the Col_num argument box. Type False in the Rang_lookup box. Click OK, is this what you were looking for?
Answer:
its best no to
Step-by-step explanation:
The only thing you can really change is switching subtraction and addiction, or division and multiplication. In the long run though its best just to say with the regural order and its earier later on.
please, (parentheses)
excuse (exponents)
my (multipliction)
dear (division)
aunt (addiction)
sally (subtraction)
-c
No , he needed to apply the exponents to all factors in the product in the second step .
Answer:
The area is pie times radius^2
The diameter is 2 times radius
The circumference is 2 times pie times radius or pie times diameter
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:
I'm going to solve 
for x using the quadratic formula:
Let's see if uv=u+v holds.
Keep in mind you are multiplying conjugates:
Let's see what u+v is now:
We have confirmed uv=u+v for k=2.
