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Ulleksa [173]
3 years ago
15

In right triangle PQR, if sinP=5/13, then tanP= 5/12 12/13 12/5

Mathematics
2 answers:
Sauron [17]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Given sinP = \frac{5}{13} = \frac{opposite}{hypotenuse}

Then the right triangle has a hypotenuse of 13 and a leg 5

Use Pythagoras' identity to find the other leg x ( adjacent)

x² + 5² = 13²

x² + 25 = 169 ( subtract 25 from both sides )

x² = 144 ( take the square root of both sides )

x = \sqrt{144} = 12 , hence

tanP = \frac{opposite}{adjacent} = \frac{5}{12}

andrew11 [14]3 years ago
4 0

Is a right triangle => P ∈ (0,90]

sinP = 5/13 => cos²P = 1 - sin²P =>

=> cos²P = 1 - 25/169 = 144/169 =>

=> cosP = +12/13 (because P ∈ (0,90])

=> tanP = sinP / cosP = (5/13)/(12/13) =

= 5/12

=> tanP = 5/12

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