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3 years ago

Very Easy Question 2/3 divided by 5.

Mathematics

1 answer:

Stella [2.4K]3 years ago

6 0

Answer:

2/15

Step-by-step explanation:

2/3 divided by 5

= 2/15

<em>Hope this helps</em>

<em>-Amelia</em>

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Joe gave 1/4 of his total candies to his classmate then he gave 4/6 of when he had left to his brother when he went home then he

Makovka662 [10]

Answer:

112

Step-by-step explanation:

Given: Joe gave 1/4 of his total candies to his classmate.

Then, he gave 4/6 of when he had left to his brother.

He gave 25% of the remaining candies to his sister.

Finally, he only had 21 candies left.

Lets assume the total number of candies at the beginning be "x".

First, finding the number candies left after giving candies to classmate.

∴ Remaining candies= $x- x\times \frac{1}{4}$

Solving it to find remaining candies after giving candies to clasmate.

⇒ Remaining candies= $x-\frac{x}{4}$

Taking LCD as 4

⇒ Remaining candies= $\frac{4x-x}{4} = \frac{3x}{4}$

∴ Remaining candies after giving candies to clasmate= $\frac{3x}{4}$

now, finding the candies left after giving candies to his brother.

∴ Remaining candies= $\frac{3x}{4} - \frac{3x}{4} \times \frac{4}{6}$

Solving it to find the remaining candies after giving candies to his brother.

⇒ Remaining candies= $\frac{3x}{4} - \frac{x}{2}$

Taking LCD 4

⇒ Remaining candies= $\frac{3x-2x}{4} = \frac{x}{4}$

∴ Remaining candies after giving candies to his brother= $\frac{x}{4}$

We know, Joe was left with only 21 candies after giving candies to his sister.

Therefore, putting an equation for remaining candies to find the number of candies at the beginning.

⇒ $\frac{x}{4} - 25\% \times \frac{x}{4} = 21$

⇒ $\frac{x}{4} - \frac{0.25x}{4} = 21$

Taking LCD 4

⇒ $\frac{x-0.25x}{4} = 21$

⇒ $\frac{0.75x}{4} = 21$

Multiplying both side by 4

⇒ $0.75x= 21\times 4$

dividing both side by 0.75

⇒ $x= \frac{21\times 4}{0.75}$

∴ $x= 112$

Hence, Joe had 112 candies at the beginning.

6 0

3 years ago

The coordinates of P and Q are (2,6) and (4,5) respectively. Equation of a line RS is Y= 2X -3. Determine if the lines are paral

Travka [436]

Answer:

Perpendicular

Step-by-step explanation:

Given points P=(2,6) and Q=(4,5)

The line RS is y=2x-3.

Now we know that the line joining any two points (x1,y1) and (x2,y2) has slope m= $\frac{y2-y1}{x2-x1}$

Now the slope of the line PQ is

m1= $\frac{5-6}{4-2}$ = - $\frac{1}{2}$

We know that the slope of the line in the form y=mx+c is m

So the line RS has slope m2=2

Now two lines are parallel if m1=m2

And those two lines are perpendicular if $m1*m2=-1$

here m1= - $\frac{1}{2}$ and m2=2

clearly $m1*m2=-1$

Therefore the two given lines are perpendicular

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3 years ago

Given that AGEO - AFUN, find UF. N G 12 ft 17 ft E O 15 ft UF = ? ft

zvonat [6]

San was a 1074774 minute walk

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3 years ago

What is the answer to 4(10 + 9)

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

10+9= 19

19*4=76

5 0

2 years ago

Read 2 more answers

Someone please help.

UkoKoshka [18]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Factorisation.

Since here both are the roots of the quadratic equation in the factor form, hence

equate them to zero, to get the value of x

hence,

2x-9 = 0

===> x = 9/2

and

3x+5=0

===> x = -5/3

6 0

3 years ago

Read 2 more answers