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3 years ago

Very Easy Question 2/3 divided by 5.

Mathematics

1 answer:

Stella [2.4K]3 years ago

6 0

Answer:

2/15

Step-by-step explanation:

2/3 divided by 5

= 2/15

Hope this helps

-Amelia

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A linen shop sells sheets and pillow cases .Linen from easiest company offer a choice in each set of sheets and pillow cassia pl

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Answer:

polkadot's strips

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polkadot's plain

Step-by-step explanation:

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2 years ago

Consider a home mortgage of $225,000 at a fixed APR of 4.5 % for 30 years. a. Calculate the monthly payment. b. Determine the

White raven [17]

The formula for the monthly payment.....

$M= \frac{P(1+r)^nr}{[(1+r)^n] -1}$ , where P = the principal amount, r = the monthly interest rate and n = the total number of months.

Here annual interest rate is given as 4.5%

So, the monthly interest rate $=\frac{4.5\%}{12}= 0.375\% = 0.00375$

Total number of months $= (30*12)months=360 months$

Also given that, the principal amount is $225000

a. So, the monthly payment will be.....

$M= \frac{P(1+r)^nr}{[(1+r)^n] -1}\\ \\ M= \frac{225000(1+0.00375)^3^6^0*0.00375}{(1+0.00375)^3^6^0 -1}\\ \\ M= \frac{225000(1.00375)^3^6^0*0.00375}{(1.00375)^3^6^0 -1} \\ \\ M \approx 1140$

Thus, the monthly payment will be approximately $1140

b. The total amount paid over the term of the loan will be: $\$ 1140*360 months = \$ 410400$

c. As the principal amount was $225000 , so the amount of interest $= (\$ 410400- \$ 225000)= \$ 185400$

So, the percentage of amount that is paid toward the principal $=\frac{225000}{410400}*100\% =54.82\%$

and the percentage of amount that is paid toward the interest $=\frac{185400}{410400}*100\%=45.18\%$

4 0

3 years ago

I WILL UPVOTE ALL ANSWERS

VikaD [51]

1. incorrect

2. correct

3. incorrect (?)

8 0

3 years ago

Read 2 more answers

What is the quadratic of X^2+5=4x

Tju [1.3M]

I hope this helps you

5 0

3 years ago

Find the extreme values of f(x y)=xy subject to the constraint x^2 + y^2 -4 = 0

KATRIN_1 [288]

Via Lagrange multipliers:

$L(x,y,\lambda)=xy+\lambda(x^2+y^2-4)$

$L_x=y+2\lambda x=0$
$L_y=x+2\lambda y=0$
$L_\lambda=x^2+y^2-4=0$

$yL_x=y^2+2\lambda xy=0$
$xL_y=x^2+2\lambda xy=0$
$\implies yL_x-xL_y=y^2-x^2=0\implies y^2=x^2$
$\implies x^2+y^2=4=2x^2\implies x^2=2\implies x=\pm\sqrt2\implies y=\pm\sqrt2$

So we have four critical points to consider, $(\sqrt2,\sqrt2),(-\sqrt2,\sqrt2),(\sqrt2,-\sqrt2),(-\sqrt2,-\sqrt2)$ . If both coordinates are positive or both are negative, we get a maximum value of $(\pm\sqrt2)^2=2$ ; otherwise, we get a minimum of $(-\sqrt2)(\sqrt2)=-2$ .

4 0

3 years ago