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3 years ago

7

I need help pleaseeeeee

1 answer:

-BARSIC- [3]3 years ago

6 0

Answer:

30

Step-by-step explanation:

total area of triangle is 180

so if 97+53= 150 180-150= 30

hope this helped

plz mark brainlest

i wanna rank up!!!

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3 years ago

How do I solve 6/2 + 8/3

Xelga [282]

Answer:

The solved given fractional expression is $\frac{17}{3}$

Therefore the given fractional expression becomes

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

Step-by-step explanation:

Given fractional expression is $\frac{6}{2}+\frac{8}{3}$

To solve the given fractional expression as below :

$\frac{6}{2}+\frac{8}{3}$

$=3+\frac{8}{3}$

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Therefore the given fractional expression becomes

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

The solved given fractional expression is $\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

7 0

3 years ago

Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9). I need help

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3 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

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Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

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With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

7 0

3 years ago

Help fast please due soon

vaieri [72.5K]

#1 m=7/4 the whole equation would be y=7/4x + 3/2

8 0

3 years ago