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lina2011 [118]
2 years ago
15

Use the concepts of kinetic energy and potential energy to describe the motion of a child on a swing. Why does the child need a

push from time to time?
Physics
2 answers:
andrew-mc [135]2 years ago
4 0
When the child is moving, he/she has kinetic energy. For just a brief second before they move the other way, the child is not moving, but they have gravitational potential energy.

The child may need a push from time to time because friction with the air causes loss of energy.
Jlenok [28]2 years ago
3 0

Answer:

The kinetic energy refers to the energy that a body has due to its speed, depends on it, the more speed the more kinetic energy will have.

The potential energy depends only on the position, specifically, the height with respect to a referential points, the more height, more potential energy will have.

These two type of energy are always exchanging from one to another, depending on the movement. When the child is swinging, he will reach a maximum point, maximum amplitude of the movement, when that point it's reached, the swing will go back. This happens because the exchange of energies.

When the swing is at maximum amplitude, the extreme points, there the kinetic energy reach the zero level, because the swing stops instantaneously. At that point of maximum amplitude, the potential energy is the higher possible, because all missing energy for kinetic is transformed as potential, this is the Conservation of Energy Theorem.

So, while the swing is moving, these two energies exchanges. The point where the potential energy is null, is the equilibrium point, when the swing passes through that point, the kinetic energy is maximum, because at that equilibrium point, the swing's height is zero.

However, this transformation of energy doesn't last forever, because it's not a perfect and controlled environment, so, the energy is constantly also transformed as heat, due to the friction of the swing. This means that after a while, the swing will stop, because the energy is producing heat, constantly. That's why the child needs to push from time to time, because the heat is subtracting energy from the system, so new input energy is needed to continue the movement.

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Exercise that strengthens your heart, increases your lung capacity, and helps you to burn fate and lose weight is..
olga2289 [7]

Answer : Cardio training

Explanation : Cardio exercise helps improve lung function , strengthens your heart and improve your endurance and increases lung capacity. The peoples do cardio is burn calories and lose the weight.

Cardio helps decrease your heart rate and blood pressure and improve your breathing.

8 0
2 years ago
A uniform plank of mass 10kg and length 10m rests on two supports, A and B as shown. A boy of weight 500N stands at a distance o
kifflom [539]

Answer:

U² = 142.86 N

U¹ = 357.14 N

Explanation:

Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)

W(2\ m) - U^2(7\ m) = 0

where,

W = weight of boy = 500 N

U² = reaction ay B = ?

Therefore,

(500\ N)(2\ m)-(U^2)(7\ m)=0\\U^2=\frac{1000\ Nm}{7\ m}\\

<u>U² = 142.86 N</u>

Now, taking summation of forces on the plank. Taking upward direction as positive, for equilibrium position:

W-U^1-U^2=0\\500\ N - 142.86\ N = U^1\\

<u>U¹ = 357.14 N</u>

3 0
2 years ago
A container with volume 1.64 L is initially evacuated. Then it is filled with 0.226 g of N2N
vaieri [72.5K]

Answer:

0.015 atm

Explanation:

The pressure of the gas can be calculated using Ideal Gas Law:

p = \frac{nRT}{V}

<u>Where:</u>

n: is the number of moles of the gas

R: is the gas constant = 0.082 L*atm/(K*mol)

V: is the volume of the container = 1.64 L

T: is the temperature

We need to find the number of moles and the temperature. The number of moles is:

n = \frac{m}{M}

<u>Where:</u>

M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol

m: is the mass of the gas = 0.226 g

n = \frac{0.226 g}{28.014 g/mol} = 8.07 \cdot 10^{-3} moles

Now, the temperature can be found using the following equation:

v_{rms} = \sqrt{\frac{3RT}{M}}    

<u>Where:</u>

R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol

v_{rms}: is the root-mean-square speed of the gas = 182 m/s

By solving the above equation for T, we have:

T = \frac{v_{rms}^{2}*M}{3R} = \frac{(182 m/s)^{2}*28.014 \cdot 10^{-3} Kg/mol}{3*8.314 J K^{-1}mol^{-1}} = 37.20 K        

Finally, we can find the pressure of the gas:

p = \frac{nRT}{V} = \frac{8.07 \cdot 10^{-3} mol*0.082 L*atm* K^{-1}*mol^{-1}*37.20 K}{1.64 L} = 0.015 atm

Therefore, the pressure of the gas is 0.015 atm.

I hope it helps you!

8 0
3 years ago
An observer sitting at a bus stop sees the bus drive by at 30 m/s to the east. He also sees a
Dafna1 [17]

Answer:

32 m/s

Explanation:

The speed of a bus is 30 m/s due East wrt the passenger

He also sees a  passenger on the bus walking to the back at 2 m/s.

We need to find the passenger's velocity relative  to the bus. As the observer sees that the bus and the passenger are moving in opposite direction. Let v is the relative velocity. So,

v = 30 m/s + 2 m/s

v = 32 m/s

Hence, the passenger's velocity relative  to the bus is 32 m/s.

8 0
3 years ago
1. What three particles are found in an atom?
Hoochie [10]

Answer:

Protons, Electrons, and neutrons

7 0
3 years ago
Read 2 more answers
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