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3 years ago

Can you access an instance variable from a static method? explain why or why not.

1 answer:

5 0

The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.

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The wet density of a gravel was found to be 2.32 Mg/m^3 and the field water content was 16%. In the laboratory, the density of t

Sholpan [36]

Answer:

the relative density of the gravel in the field is 0.7365 or 73.65%

Explanation:

Given that;

wet density of gravel $r_{b}$ = 2.3 Mg/m³

field water content w = 16%

density of solids in lab $r_{s}$ = 2.70 Mg/m³

Maximum void ratio $e_{max}$ = 0.59

Minimum void ratio $e_{mini}$ = 0.28

first we determine the dry density of gravel $r_{d}$ = $r_{b}$ / 1+ w

$r_{d}$ = 2.3 Mg/m³ / 1 + 0.16 = 2.3/1.16 = 1.9827 Mg/m³

we know that; $r_{w}$ = 1000 kg/m³ = 1 g/cm³

Specific Gravity of soil G = $r_{s}$ / $r_{w}$ = 2.70 Mg/m³ / 1 = 2.70 Mg/m³

eo = ((G× $r_{w}$ )/ $r_{d}$ ) - 1

eo = (( 2.70 × 1) / 1.9827 ) - 1

eo = 1.3617 - 1

Co = 0.3617

so Relative density $I_{D}$ will be;

$I_{D}$ = $e_{max}$ - eo / $e_{max}$ - $e_{mini}$

we substitute

$I_{D}$ = 0.59 - 0.3617 / 0.59 - 0.28

$I_{D}$ = 0.2283 / 0.31

$I_{D}$ = 0.7365 or 73.65%

Therefore; the relative density of the gravel in the field is 0.7365 or 73.65%

3 0

3 years ago

Heating a metal from room temperature to pouring temperature in a casting operation depends on all of the following properties e

lapo4ka [179]

Answer:

(e) thermal expansion

Explanation:

The density, the heat of fusion and the melting temperature of the metal are determining characteristics to take into account to raise the temperature of the metal from room temperature to the melting temperature. Since they will determine the following:

Density: is the relationship between the mass of a body and the volume it occupies in outer space.

Heat of fusion: The enthalpy of fusion or heat of fusion is the amount of energy needed to make a mole of an element that is at its melting point pass from the solid state to the liquid, at constant pressure.

Melting temperature is defined as the temperature at which the phase transition from the solid state to the liquid occurs at normal atmospheric pressure.

While the dilution of metals will only have an influence on the volume it will occupy but not on the heating process

7 0

3 years ago

Is it possible to determine from the data in the graphs whether the sensor attached to cart a is actually plugged into ch a and

ladessa [460]

It is possible to determine which cart to which ch is connected if the graph would show electrical charge, ie, amps or voltage. If the graph showed a series circuit diagram this would also allow determination. Bottom line is that a correct graph data will show the requested information.

4 0

3 years ago

Which of the following statements are true? (There may be more than one correct choice.)

Luba_88 [7]

Answer:

option (A)

Explanation:

According to the Archimede's principle, when a body s immersed partly or wholly in a liquid, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in the weight of body.

The weight of liquid displaces by the body is equal to the loss in weight of body.

Thus, option (a) is true.

5 0

3 years ago

A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve

amm1812

Answer:

The velocity of the tennis racket after the collision 14.966 m/s.

Step-by-step explanation:

let the following:

m₁ = mass of tennis racket = 0.311 kg

m₂ = mass of the ball = 0.057 kg

u₁ = velocity of tennis racket before collision = 30.3 m/s

u₂ = velocity of the ball before collision = -19.2 m/s

v₁ = velocity of tennis racket after collision

v₂ = velocity of the ball after collision

Right (+) , Left (-)

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

So, the total kinetic energy before collision = the total kinetic energy after collision.

So, 0.5 m₁ u₁² + 0.5 m₂ u₂² = 0.5 m₁ v₁² + 0.5 m₂ v₂² ⇒ (1)

Also, the total momentum before collision = the total momentum after collision.

So, m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂ ⇒ (2)

Solving (1) and (2):

∴ v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

= ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)

= 14.966 m/s.

So, the velocity of the tennis racket after the collision 14.966 m/s.

7 0

3 years ago