The De Broglie's wavelength of a particle is given by:
where
is the Planck constant
p is the momentum of the particle
In this problem, the momentum of the electron is equal to the product between its mass and its speed:
and if we substitute this into the previous equation, we find the De Broglie wavelength of the electron:
So, the answer is True.
Answer:
The range of powers is
Explanation:
From the question we are told that
The far point of the left eye is
The near point of the left eye is
The near point with the glasses on is
From these parameter we can see that with the glass on that for near point the
Object distance would be
Image distance would be
To obtain the focal length we would apply the lens formula which is mathematically represented as
substituting values
converting to meters
Generally the power of the lens is mathematically represented as
Substituting values
From these parameter we can see that with the glass on that for far point the
Object distance would be
Image distance would be
To obtain the focal length of the lens we would apply the lens formula which is mathematically represented as
substituting values
converting to meters
Generally the power of the lens is mathematically represented as
Substituting values
This implies that the range of powers of the lens in his glass is