Write a fraction greater than 1 for 5 using 6 as the denominator.

Mathematics

1 answer:

Inessa05 [86]3 years ago

4 0

4/6 can be one because the denominator is 6

You might be interested in

Help please 100 points if you do

Artist 52 [7]

U scammer it only says 5 points not 100

3 0

3 years ago

How to convert nonlinear equation to linear equation?

9966 [12]

Let's take the non-linear equation:
${x}^{2} = \sqrt{3} y$
First Make The Equation To Be In Terms of Y

*Divide Both sides by
$\sqrt{3}$
$\frac{ {x}^{2} }{ \sqrt{3} } = \frac{ \sqrt{3} y}{ \sqrt{3} }$
*Simplify
$\frac{ {x}^{2} }{ \sqrt{3} } = y$
You shouldn't keep a radical in the denominator, however we leave it for the purpose of the reciprocal.

*Take The Reciprocal Of Both Sides
$\frac{ \sqrt{3} }{ {x}^{2} } = \frac{1}{y}$
A Linear Equation Takes The Format:
$y = mx + b$
So,
$\frac{1}{y} = y$
$b = 0$
$m(slope) = \frac{ \sqrt{3} }{x}$
$x = \frac{1}{x}$
Resulting in :
$\frac{1}{y} = \frac{ \sqrt{3} }{x} (\frac{1}{x} ) + 0$

4 0

3 years ago

The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the

grin007 [14]

Answer:

8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

25 = AB + BC + AC

25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

20 = 5/3·AB

12 = AB

AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.