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DedPeter [7]
3 years ago
8

In throwing a die what is the probability of getting even or prime number​

Mathematics
1 answer:
Julli [10]3 years ago
5 0

die number : 1 2 3 4 5 6

<em>p</em><em>r</em><em>o</em><em>b</em><em>a</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>o</em><em>f</em><em> </em><em>g</em><em>e</em><em>t</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>e</em><em>v</em><em>e</em><em>n</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>:</em><em> </em><em>3</em><em>/</em><em>6</em>

because the number 2,4,6 are even number

the number 3 is 'how many even number?'

while 6 is the total number in throwing a die

<em>p</em><em>r</em><em>o</em><em>b</em><em>a</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>o</em><em>f</em><em> </em><em>g</em><em>e</em><em>t</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>p</em><em>r</em><em>i</em><em>m</em><em>e</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em> </em><em>:</em><em> </em><em>2</em><em>/</em><em>6</em>

because the number 3,5 are only prime number

the number 2 is 'how many prime number?'

while 6 is the total number in throwing a die

the question ask : getting even OR prime number

this means that we have to add the probability of even and prime number

3/6 + 2/6 = 5/6 (answer)

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