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Liula [17]
3 years ago
8

Determine the interval(s) on which the function is (strictly) decreasing.

Mathematics
2 answers:
ANEK [815]3 years ago
5 0
The intervals where the function are strictly decresing are (-3, -2) ∪ (4, 6)
Luda [366]3 years ago
5 0
It's strictly increasing on: [-7,-6]∪[1,3]. 
<span>It's increasing on: [-7,-2]∪[1,3].</span>
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HELP HELP !! &amp; PlEASE SHOW WORK ! What would be the compound interest rate if Tom borrowed $6,000 at a 3% interest rate for
In-s [12.5K]

Answer:

Compound interest = $365.4

Step-by-step explanation:

Given:

Amount borrowed = $6,000

Rate of interest = 3%

Number of year =  year

Find:

Compound interest

Computation:

A = P[1+r]ⁿ

Amount after 2 year = 6,000[1 + 3%]²

Amount after 2 year = 6,000[1 + 0.03]²

Amount after 2 year = 6,000[1.03]²

Amount after 2 year = 6,000[1.0609]

Amount after 2 year = 6,365.4

Compound interest = Amount after 2 year - Amount borrowed

Compound interest = 6,365.4 - 6,000

Compound interest = $365.4

3 0
2 years ago
Jeff needs to create a password for his E-mail account. The password must have four letters. How many different passwords can he
Flura [38]

Answer:

uh what about bang thats four words id.k

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Jada invest $590 in a money market account. Her account pays 7% simple interest. How much interest will Jada earn after 4 years
mote1985 [20]

Answer:

165.2

Step-by-step explanation:

7%x4=28

28 percent of 590 = <u>165.2</u>

7 0
2 years ago
if an orange gets cut in half how much do you have left if you cut in forths how many slices are there​
a_sh-v [17]

Answer:

There are 10 slices left

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
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