Question

What is the solution of log2 (3x - 7) = 3?

Answer 1

ANSWER

The solution is

$x = 5$
EXPLANATION


We want to solve the logarithmic equation

$log_{2}(3x - 7) = 3$
We take the antilogarithm of both sides to base 2.


In order words we need to rewrite the logarithmic equation as an exponential equation,

This implies that,


$(3x - 7) = {2}^{3}$


We evaluate the right hand side of the equation to obtain,


$3x - 7 = 8$


We group the constant terms on the left hand side of the equation to obtain,


$3x = 8 + 7$

This implies that

$3x=15$

$x = 5$

Answer 2

I hope this helps you