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3 years ago

When 2 times a number is increased by 9, the answer is the same as

Mathematics

1 answer:

adelina 88 [10]3 years ago

5 0

Answer:

its 7

Step-by-step explanation:

why did u delete my answer if its right?

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5p= 112.50. The 5 members of the Wyler family paid 112.50 for admission to a water park. What was the price ,p, of each ticket

Ivahew [28]

The price for each ticket is 22.41

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3 years ago

PLEASE HELP ME I DON T UNDERSTAND IF YOU PLEASE COULD HELP ME I WOULD GREATLY APPRECIATE IT REALLY THANK YOU

butalik [34]

Find the length of one side.

V = s^3

s = cube root of V

V = 729

s = cube root 729

s = 9

Put this into your calculator as 729^0.333333333

It should bring back 9 or 8.999999 something which means 9.

Net

The net is shown below. You will have to do the labeling. But I can tell you what you should label each face as?

Area of one face = s^2

s = 9

Area of one face = 9*9

Area of one face = 81

So when you draw this, each face should be labeled with 81.

It should have it's units (ft^2) if your marker is picky.

Part C

There are 6 sides.

1 side has an area of 81 ft^2

6 sides have an area of 6*81 = 486 ft^2

5 0

3 years ago

Can someone help me with this please?

Pepsi [2]

The 5x5 square grid has 6 , 2 x 2 subgrids and the least value of n for which you can be certain that it will have a 2 x 2 subgrid of grey squares is 12.

<h3>What is a Square ?</h3>

A square is a polygon with four sides and all the sides are equal and parallel and all the angle value is 90 degree.

(a) The 5x5 square grid has 6 , 2 x 2 subgrids.

(b) the least value of n for which you can be certain that it will have a 2 x 2 subgrid of grey squares is 12

as it can be understood from the figure 2 that only the last square doesn't have a pair and the rest all does

more than that will be extra but 12 will be enough to make all the grey squares of 2 x 2 subgrid .

To know more about Square

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4 0

1 year ago

X+4x +6x= Simplify each expression

lozanna [386]

You add like terms together
1x+4x+6x are like terms

=11x

3 0

2 years ago

Read 2 more answers

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

3 years ago