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3 years ago

HELP giving BRAINLIEST !!!!

Mathematics

2 answers:

Effectus [21]3 years ago

6 0

Answer:

ohhhh cool i go to the same school

Step-by-step explanation:

miss Akunina [59]3 years ago

4 0

One question before I give my answer , Where did it say she stopped?

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Find an equation of the circle that satisfies the given conditions:

Anna71 [15]

Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.

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3 years ago

Factor 2x2 - 13x - 70

sladkih [1.3K]

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3 years ago

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If the starting time is 7:43 and the elapsed time is 36 minutes then what time what is the ending time

Annette [7]

Answer:

8:19

Step-by-step explanation:

It is 17 minutes until 8:00. 36 - 17 = 19 minutes left.

8:00 + 19 minutes = 8:19

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3 years ago

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2x^4–5x^3+x^2+3x+2=? X=5

DanielleElmas [232]

Answer:

$2x^4–5x^3+x^2+3x+2=$

$2 \times 5^4–5 \times 5^3+5^2+3 \times 5+2$

= 2 × 625 – 5 × 125 + 25 + 3 × 5 + 2

=1250 – 625 + 25 + 15 +2

= 1292 – 625

= 667

3 0

3 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

2 years ago