Ask question

Ask question

All categories

3 years ago

12

Please help, This is due soon!!! I’ll mark brainiest or what ever it is called

2 answers:

umka2103 [35]3 years ago

3 0

Answer:

c and d

Step-by-step explanation:

using the two angles in the triangle, 1 and 2, it can be 180- the sum of angles 1 and 2, which is c. using angle 4, it can also be 180 - the equation for angle 4

GuDViN [60]3 years ago

3 0

Answer:

C and D

Step-by-step explanation:

Choice C says that if you take 180 minus the sum of angles 1 and 2, you will find the measure of angle 3. Choice D says that is you take 180 minus angle 4, you will find the measure of angle 3 due to both angles forming a straight angle.

You might be interested in

When Rachel puts gas in her car, she records the distance that she has driven since her last

Free_Kalibri [48]

g=0.04 times d

Step-by-step explanation:

if you multiply 0.04 with every number under the d column then you’ll get the outcome of each number under g

6 0

3 years ago

Rohit rides his bike 4 1/5 miles in 20 minutes. At this rate, how far can he bike in 1 hour?

Mila [183]

He can bike 12.6 miles

4 0

3 years ago

Read 2 more answers

A town's total allocation for firefighter's wages and beneﬁts in a new budget is $600,000. If wages are calculated at $40,000 pe

tiny-mole [99]

There is 8 firefighters

4 0

2 years ago

A central angle θ in a circle of radius 4 m is subtended by an arc of length 5 m. find the measure of θ in degrees. (round your

koban [17]

Answer:

$\theta=71.6\°$

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

$C=2\pi r$

we have

$r=4\ m$

substitute the values

$C=2\pi (4)=8 \pi\ m$

step 2

Remember that

360 degrees subtends the arc of length $8 \pi\ m$ (circumference)

so

by proportion

Find the measure of θ by an arc of length 5 m

assume $\pi=3.1416$

$\frac{360}{8\pi}=\frac{\theta}{5}\\ \\ \theta=360*5/8\pi \\ \\ \theta=71.6\°$

5 0

3 years ago

For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?

kvv77 [185]

Answer: Option C

$f(x) = x^2;\ k (x) = x ^ 2 -7$

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

$k (x) = f (x) + b$

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

$f (x) = x ^ 2$

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

$k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7$ .

Then the function k(x) that will have its vertex 7 units below f(x) is

$k (x) = x ^ 2 -7$

3 0

3 years ago