Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
It would be the negative form of those bumbers and the non-negative form of those numbers. The absolute value applies to negative numbers the same. For example absolute value of -3 is 3.
11/42
The way I got it is because I took 1/6 minus 3/7 to get the answer of f=11/42
Answer:
See the image for solution.
Brainlist please
