Explanation:
(a) The given data is as follows.
Temperature (T) =
= (25 + 273) K = 298 K
= 43000 J/mol
Since, both the liquid and vapors are at equilibrium. Therefore, change in free energy will be calculated as follows.
= 0
43000 -
= 0
= -144 J/mol K
Negative sign indicates an increase in entropy of the system.
Now, for 1 mole of
is as follows.
= 144 J/K
So,
- 214 = 144 J/k
= 358 J/K
Therefore, we can conclude that entropy of
vapor is 358 J/K.
(b) As we know that intensive variable are the variables which do not depend on the amount of a substance.
So, in the given situation only temperature will act as an intensive variable that will be required to completely specify the vapor-liquid mixture of
.
Answer:
Explanation: A chemical change is a reaction in which chemical composition of the substance changes. Some bonds are broken and some new bonds are formed.
The reactants are written in terms of their chemical formula on the left hand side and the products are written in terms of their chemical formula on right hand side with a arrow in between. The chemical symbols are followed by their physical states such as (l) for liquid, (s) for solid, (g) for gas and (aq) for aqueous.
Thus the only reaction producing a gas is 
Answer:
It is the energy the ions absorb when they form a crystalline compound.
Explanation:
Lattice energy is the energy released upon the formation of a crystal lattice structure.
Explanation:
We can summarize the reaction shown as:
2F₂ + I₂ → 2F₃I
Since I is purple
F is the green
The number of I atoms in the reactants is greater than the number in the product
False:
The number of I atoms on both side of the expression is 2
There are 4 atoms of F in both the reactants and the products.
False:
There are 4 atoms of F on the reactant side and 6 atoms of F on the product side
The illustration represents a valid chemical transformation. True or false
False
The reaction does not represent a valid chemical transformation because in a valid chemical transformation, the number of atoms on both sides of the expression must be the same.