Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.
Explanation:
density
ρ
=
Mass
Volume
, and thus units of
g
⋅
m
L
−
1
are reasonable.
For this problem:
17.4
⋅
m
L
×
0.798
⋅
g
⋅
m
L
−
1
≅
14
⋅
g
but A i supposed?
Answer:
The intermolecular forces between CO3^2- and H2O molecules are;
1) London dispersion forces
2) ion-dipole interaction
3) hydrogen bonding
Explanation:
Intermolecular forces are forces of attraction that exits between molecules. These forces are weaker in comparison to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.
Considering CO3^2- and H2O, we must remember that hydrogen bonds occur whenever hydrogen is bonded to a highly electronegative atom such as oxygen. The carbonate ion is a hydrogen bond acceptor.
Also, the London dispersion forces are present in all molecules and is the first intermolecular interaction in molecular substance. Lastly, ion-dipole interactions exists between water and the carbonate ion.
Answer: 36.53g
Explanation:
First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl
Molarity = 5M
MM of NaCl = 58.45
Molarity = Mass conc (g/L) / MM
Mass conc. (g/L) of NaCl = Molarity x MM
= 5 x 58.45 = 292.25g
Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)
From the calculations above,
292.25g of NaCl dissolved in 1L
Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e
Xg of NaCl = 292.25 x 0.125 = 36.53g.
Therefore 36.53g of NaCl will dissolve in 125mL of the solution
Water isn’t wet, Wetness is a description of our experience with water. What happens to us when we come in contact with water is called being wet
Explanation:
As we know that the atomic number of lithium is 3 and its electronic distribution is 2, 1. Whereas atomic number of fluorine is 9 and its electronic distribution is 2, 7. So, for a metal it is easier to lose an electron rather than losing 2 or more number of electrons.
Also, fluorine is much more electronegative in nature. Hence, it will readily accept an electron from a donor atom. Therefore, a strong ionic bond will be present between lithium and fluorine atom.
On the other hand, atomic number of magnesium is 12 and its electronic configuration is 2, 8, 2. And, atomic number of oxygen is 8 and its electronic distribution is 2, 6. Also, oxygen is less electronegative than fluorine therefore, force of attraction exerted by oxygen to gain the valence electrons will not be strong enough.
Hence, the ionic bond between magnesium oxide is not strong enough.
Thus, we can conclude that ionic bond between lithium fluoride is stronger than ionic bond in magnesium oxide.
