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Stella [2.4K]
4 years ago
8

What volume of 0.225 m k3po4 solution is necessary to completely react with 134 ml of 0.0112 m nicl2?

Chemistry
2 answers:
kozerog [31]4 years ago
8 0

Answer:

Explanation:?

OleMash [197]4 years ago
3 0
To answer this question, you need to know the equation for the reaction. The equation should look like this:
<span>2K3PO4 (aq) + 3NiCl2 (aq) --> Ni3(PO4)2 (s) + 6KCl (aq) 
</span>
In the equation, 2 K3PO4 would react with 3 NiCl2. Then the calculation should be look like this:
V2= V1*m1/m2 *2/3
V2= 134ml * <span>0.0112/</span>0.225 *2/3
V2= 4.46ml
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