All categories

3 years ago

Given points A (-8,7) and B (6, -9), find the midpoint, M

Mathematics

1 answer:

Vladimir [108]3 years ago

7 0

Hey there! I'm happy to help!

To find the x value of the midpoint, you add the 2 x values and divide by 2.

-8+6=-2

-2/2=-1

For the y value, you do the same thing but with the y values.

7-9=-2

-2/2=-1

Therefore, our midpoint is (-1,-1).

Have a wonderful day! :D

You might be interested in

Which polynomial function of lowest degree with rational real coefficients

vfiekz [6]

Answer:

a polynomial with degree coefficient real number can be a negative number

i guessed i am not sure

7 0

2 years ago

Find the equation of the function in the graph.

GuDViN [60]

D. y = x^2 because it is a parabola so the function needs to be quadratic

8 0

3 years ago

Read 2 more answers

Which describes the correct way to convert minutes hours

masha68 [24]

60 minutes=1 hour, so to convert minutes to hours,<em> divide by 60.</em>

5 0

3 years ago

Read 2 more answers

A new car is purchased for 17300 dollars. The value of the car depreciates at 9.25% per year. What will the value of the car be,

r-ruslan [8.4K]

Answer: 13

i got the question wrong and it told me the correct answer . thank me later

4 0

2 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

1 year ago