1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir2022 [97]
3 years ago
11

If you wanted to watch a cell swim in a drop of pond water which microscope will you use

Biology
1 answer:
TiliK225 [7]3 years ago
4 0

The answer will definitely be B) Compound Light Microscope because other cells can die from the other microscope, and their to powerful, so they can't handle it.

You might be interested in
The mitochondria in our cells release energy (ATP). What is the life function are they performing?
adoni [48]

Answer: The main function of mitochondria is to produce energy for the cell. Cells use a special molecule for energy called ATP.

Explanation: The most prominent roles of mitochondria are to produce the energy currency of the cell, ATP (i.e., phosphorylation of ADP), through respiration, and to regulate cellular metabolism. The central set of reactions involved in ATP production are collectively known as the citric acid cycle, or the Krebs cycle.

8 0
2 years ago
Zaznacz odpowiednie wyrazy.
lianna [129]

Answer:

I don't get what you are trying to ask

4 0
3 years ago
The human population is predicted to continue increasing as the rate of climate change also increases. What technology doesn't
ioda

Answer:

c

Explanation:

i had a test.

6 0
3 years ago
In your experiment, you found the following offspring only:Tall green: 626 offspring.Tall yellow: 313 offspring.Short green: 309
Karo-lina-s [1.5K]

Complete question:

1. You found a new species of garden pea and have decided to repeat Mendel’s experiments. You have obtained two true-breeding pea plants that are tall (T) with yellow pods (g), and short (t) with green pods (G), respectively. Capital letters indicate dominant traits.

a. What is the genotype and phenotype of the F1 generation? (2p)

b. You allowed self-fertilization in F1 generation and obtained F2 generation. Using Punnett square to obtain the phenotypes, genotypes and their respective ratios. (4p)  

2. If you obtained 1248 offspring in the F2 generation in Question 1, calculate how many offspring of each phenotypic class you would expect to have. (4p)

3. When you finish questions 1 and 2, under what assumption/hypothesis did you perform your analysis/calculation? Is there an alternative assumption/hypothesis, which may result in a different conclusion? If yes, what is the alternative assumption/hypothesis and what kind of offspring and in what numbers do you expect to obtain? (4p)    

4. You only need to answer A or B to get this 6p. Please indicate which question you are answering. In your experiment, you found the following offspring only: Tall green: 626 offspring. Tall yellow: 313 offspring. Short green: 309 offspring.  

A: If you stay with your original hypothesis/assumption, test it using chi2 test and analyze the result (whether you want to reject the hypothesis and why).

B: If you believe that the alternative hypothesis fits better with your data, test it using chi2 test and analyze the result (whether you want to accept the hypothesis and why).

Answer:

1) a. 100% of the progeny will be dihybrid, TtGg, exhibiting the phenotype    

       Tall plants with green pods.

   b.  F2 Gentotype:

  • 1/16 TTGG
  • 2/16 TTGg
  • 1/16 TTgg
  • 2/16 TtGG
  • 4/16 TtGg
  • 2/16 Ttgg
  • 1/16 ttGG
  • 2/16 ttGg
  • 1/6 ttgg

      F2 Phenotype:

  • 9/16 Tall plants with green pods (T-G-)
  • 3/16 Tall plants with yellow pods (T-gg)
  • 3/16 Short plants with green pods (ttG-)
  • 1/16 Short plants with yellow pods (ttgg)

Phenotypic ratio → 9:3:3:1

2)  T-G- → 702 individuals

     T-gg → 234 individuals

     ttG- → 234 individuals

     ttgg → 78 individuals

3)

  • Null Hypothesis: The population is under Hardy-Weinberg equilibrium. The alleles of this population assort independently.
  • Alternative Hypothesis: The population is not in equilibrium. Alleles do not assort independently.

4) a. There is enough evidence to <u>reject the null hypothesis</u>, meaning that the difference between the observed number of individuals and the expected ones is statistically significant. The population is not under equilibrium H-W. Alleles do not assort independently.  

Explanation:

1) 1st Cross: True-breeding tall (T) with yellow pods (g) pea plant with a short (t) with green pods (G) plant

  • Tall and Green pods are the dominant traits,
  • Short and yellow pods are recessive traits.

Parentals)         TTgg         x         ttGG

Gametes) Tg, Tg, Tg, Tg          tG, tG, tG, tG

F1) 100% of the progeny will be dihybrid, TtGg, exhibiting the phenotype    

    Tall plants with green pods.

2nd Cross: F1 self-fertilization

Parentals)  TtGg     x     TtGg

Gametes) TG, Tg, tG, tg

                TG, Tg, tG, tg

Punnett square)    TG         Tg           tG          tg

                 TG      TTGG     TTGg      TtGG      TtGg

                 Tg       TTGg      TTgg      TtGg      Ttgg

                 tG        TtGG      TtGg       ttGG       ttGg

                  tg        TtGg       Ttgg       ttGg       ttgg

F2) Gentotype:

  • 1/16 TTGG
  • 2/16 TTGg
  • 1/16 TTgg
  • 2/16 TtGG
  • 4/16 TtGg
  • 2/16 Ttgg
  • 1/16 ttGG
  • 2/16 ttGg
  • 1/6 ttgg

      Phenotype:

  • 9/16 Tall plants with green pods (T-G-)
  • 3/16 Tall plants with yellow pods (T-gg)
  • 3/16 Short plants with green pods (ttG-)
  • 1/16 Short plants with yellow pods (ttgg)

Phenotypic ratio → 9:3:3:1

2) The total number of individuals in the F2 is 1248.

16 ----------------- 1248 individuals  --------------- 100% of the progeny

9 T-G- ----------- X = 702 individuals-------------X = 56.25%

3 T-gg ----------- X = 234 individuals ----------- X = 18.75%

3 ttG- ------------- X = 234 individuals ---------- X = 18.75%

1 ttgg ------------- X = 78 individuals ------------ X = 6.25%

3)

  • Hypothesis: The population is under Hardy-Weinberg equilibrium. The alleles of this population assort independently.
  • Alternative Hypothesis: The population is not in equilibrium. Alleles do not assort independently

4)    F2 composed of:

  • Tall green: 626 offspring.
  • Tall yellow: 313 offspring.
  • Short green: 309 offspring.  

                       Tall/Green        Tall/Yellow         Short/Green       Short/Yellow

Observed              626                  313                        309                        0

Expected               702                  234                       234                       78

(Obs-Exp)²/Exp     8.23                  26.7                        24                        78

X² = Σ(Obs-Exp)²/Exp = 8.23 + 23.7 + 24 + 78 = 136.93 ≅ 137

Freedom degrees = genotypes - number of alleles = 9 - 4 = 5

Significance level, 5% = 0.05

Table value/ Critical value = 11.07

X² = 137

X² > Critica value

137 > 11.07

There is enough evidence to <u>reject the null hypothesis</u>, meaning that the difference between the observed number of individuals and the expected ones is statistically significant. The population is not under equilibrium H-W. Alleles do not assort independently.    

5 0
3 years ago
"Cell biologists have introduced radioactively labeled carbohydrates, fats and amino acids to living cells, allowed time for cel
Delicious77 [7]

Answer:

The correct answer will be- the cell structures undergo repeated breakdown and formation.

Explanation:

The carbohydrates, fatty acids and amino acids are the three important bio-molecules which form the components of various cellular structures.

In the given question, the cell biologist radiolabeled these biomolecules and then observed the cellular structures after cell metabolism. He found that few cellular structures contained radiolabeled structures and few not. This showed that the cellular structures constantly undergo changes in their structures due to cellular metabolic reactions and are broken down and reformed.

Thus,  the cell structures undergo repeated breakdown and formation is the correct answer.

7 0
2 years ago
Other questions:
  • Many species of fish live in groups known as shoals. Shoals of fish can live and travel together for part or all of their lives.
    6·1 answer
  • What type of drink has Ethanol and Lactate in it?
    6·1 answer
  • Stimulation of appetite occurs mostly from ________________ cues.
    6·1 answer
  • BRAINLIEST! Can bubbles be different shapes? Write one or two sentences.
    14·1 answer
  • What are some closely related animals to the Marine Iguana?
    14·1 answer
  • Which would a diet low in carbohydrates most likely promote? *
    11·2 answers
  • Which owl was most fit?
    6·1 answer
  • Please help i’m on a timer
    6·1 answer
  • Which factor influences the early detection of a childhood disease by a physician?
    6·1 answer
  • The structure of dna and the possible base pairs it contains
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!