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amm1812
3 years ago
11

two different floor plans are being offered in a new housing development. several prospective buyers from three different age gr

oups were surveyed about which plan they preferred. find the probability that a randomly selected by her preferred plan a or was in the 40-to 49-year-old age group. (The answer is not 0.912)

Mathematics
1 answer:
Lesechka [4]3 years ago
7 0
<h3>Answer: Approximately 0.677</h3>

Explanation:

Add up the values in the plan A column. There are 10+12+16 = 38 people who prefer plan A.

Add up the values in the "40-49" row to find that 16+8 = 24 people are ages 40 to 49.

We have 38+24-16 = 46 people who either prefer plan A, are aged 40-49, or fit both descriptions. I subtracted off 16 because those 16 people were counted twice when adding 38 and 24.

An alternative way to get this value of 46 is to add up everything that is in column1 or row 3 (or both). So that would get 10+12+16+8 = 46.

Now add up everything in the table to find out how many people were surveyed total. That would be 10+7+12+15+16+8 = 68 people overall.

The probability of someone liking plan A, or being age 40-49, or both is 46/68 = 0.6765 approximately. Rounding to 3 decimal places gives 0.677

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musickatia [10]

Answer:

4.42857142857 but since we are rounding to the nearest hundredth it would be 4.43

Step-by-step explanation:

You would add all the numbers together (7+4+2+6+4+5+3=31) then you would divide by the number or numbers there is (31 divided by 7= 4.42857142857) then round to the nearest hundredth (4.43000000000 = 4.3)

5 0
3 years ago
The chief chemist for a major oil and gasoline production company claims that the regular unleaded gasoline produced by the comp
Svetradugi [14.3K]

Answer:

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621

Step-by-step explanation:

This is a normal distribution problem

The mean of the sample = The population mean

μₓ = μ = 4 ounces

But the standard deviation of the sample is related to the standard deviation of the population through the relation

σₓ = σ/√n

where n = Sample size = 100

σₓ = 1.2/√100

σₓ = 0.12

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)

To do this, we first normalize/standardize the 4.3 ounces

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5

To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)

We'll use data from the normal probability table for these probabilities

P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621

5 0
4 years ago
The cost in dollars of producing x units of a particular brand of notebook is C(x) = x2 – 400.
yulyashka [42]
<span>
A)
C(102) = 102^2 – 400 = 10004
</span>C(100) = 100^2 – 400 = 9600

average rate of change = (10004<span>- 9600)/(102 - 100) = 404/2 = 202

</span>B)
C' = 2x = 2 (100) = 200
8 0
4 years ago
You are baking brownies for your class. There are 28 total students in your class and you have baked 23 brownies. Write and solv
barxatty [35]

Answer:

2(28)=23+x

Step-by-step explanation:

There are 28 students and each student needs two brownies. You have to multiply 28 by 2 so you will have to total number on one side.

On the other you need to have the number of brownies you have at the moment and x for the number you need to bake. You want to add them because you will need to put those numbers together to get the number on the opposite side.

28x2=56 so 56=23+x. Subtract the 23 from both sides to get 33=x. x=33

To check plug 33 into x to get 2(28)=23+33. 56=23+33. 56=56

you need 33 more brownies.

So the equation would be 2(28)=23+x.

Hope that helps.

3 0
3 years ago
-3x to the fourth power -3x to the third power+x squared-2x to the third power -xsquared -8x +6
Ede4ka [16]

Given the sum:

\begin{gathered} -3x^4-3x^3+x^2 \\ \ldots\ldots-2x^3-x^2-8x+6 \end{gathered}

The sum is given below:

Therefore, the sum of the polynomials is:

-3x^4-5x^3-8x+6

5 0
1 year ago
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