Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab
Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)
2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}
Answer:
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
Answer:
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