We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k







............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k




Since, this is absolute function
so, we can break it into two parts


we get




so,
...............Answer
I'm assuming the question is
A company pays its employees a fixed base salary and a commission based on sales. The scatter plot shows the total earning of an employee of the company (y) based on sales (x):
Plot the ordered pairs 0, 10 and 100, 20 and 200, 30 and 300, 40 and 400, 50 and 500, 60
Which function best represents the data in the scatter plot? (1 point)
y = 0.1x + 10
y = 0.1x − 10
y = 0.1x + 1
y = 0.2x − 1
So thus your answer would be y = 0.1x + 10
X2 - 25 = 0
Add 25 on each side.
x2 = 25
Divide by 2 on each side.
x = 12.5
PV=FV/(1+i)^t
FV=7000, i=3.5%=0.035,t=9
put everything in the formula
PV=7000/(1+0.035)^9
PV=$5136.12