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4 years ago

5

19. The work done by a magnetic field on a charged particle moving in it is:

1 answer:

Tresset [83]4 years ago

4 0

Answer:

The work done by a magnetic feild on a chraged particle moving in it is zero

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PLEASE PLEASE HELPPP

Digiron [165]

The answer to your question is $-5m/s^2$ or C.

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4 years ago

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Determine the identity of an unknown element X using the given table and following clues: I) Element X is a solid II) Element X

klasskru [66]

The answer is calcium. I just did it and it was correct

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3 years ago

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Which words best describe the archer's results?

Inessa [10]

The words best describe the archer's results are The correct option is A.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Given is an archer's targets on the target board.

Accuracy compares the experimental value to the theoretical value (desired target)

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is A.

Learn more about accuracy.

brainly.com/question/13099041

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7 0

2 years ago

A mass is oscillating horizontally on a spring. At the locations A, B, C, D, and E, photogates are used to measure the speed of

svetoff [14.1K]

Complete Question

The complete question is is shown on the first uploaded

Answer:

The elastic potential energy at point B is $PE_{elastic} = 50J$

The kinetic energy at point D is $KE = 75J$

Explanation:

Looking at the given point we can observe that mechanically energy(i.e potential and kinetic energy ) is conserved and it value is $E_ {m} = 100J$

So at point B

$E_{m} = PE_{elastic} +KE$

$100 = PE_{elastic} + KE$

KE at point B is 50J

So $PE_{elastic} = 100 - 50 = 50J$

Now at point D

$E_{m} = PE_{elastic} +KE$

$PE_{elastic}$ at point D is 25J

So $KE = 100 - 25 = 75J$

4 0

3 years ago

A 25 kg rock falls for 2.7 seconds. How many meters tall was the building?

sertanlavr [38]

Answer:

35.7m

Explanation:

Given parameters:

Mass of rock = 25kg

Time of fall = 2.7s

Unknown:

Height of the building = ?

Solution:

To solve this problem, we will use one of the motion equations;

S = ut + $\frac{1}{2}$ gt²

S is the height

u is the initial velocity = 0m/s

t is the time

g is the acceleration due to gravity

S = (0 x 2.7) + $\frac{1}{2}$ x 9.8 x 2.7² = 35.7m

5 0

3 years ago