Answer:
h= 46.66 m
Explanation:
Given that
Initial speed of the car ,u = 110 km/h
We know that
1 km/h= 0.277 m/s
u= 30.55 m/s
lets height gain by car is h.
The final speed of the car will be zero at height h.
v²=u²- 2 g h
v= 0 m/s
0²=30.55²- 2 x 10 x h ( g = 10 m/s²)
h= 46.66 m
Answer:
B) 12 m
Explanation:
Gravitational potential energy is:
PE = mgh
Given PE = 5997.6 J, and m = 51 kg:
5997.6 J = (51 kg) (9.8 m/s²) h
h = 12 m
Answer:
= 40 cm
Explanation:
given data
string length = 30 cm
solution
we take here equation of length that is
L = 
...............1
so
total length will be here
so will be
= 40 cm
Answer:
22 km/h
Explanation:
Given that,
Speed of Xavier, v = 14 km/h
He tosses a set of keys forward on the ground at 8 km/h, v' = 8 km/h
We need to find the speed of the keys relative to the ground. Let it is V.
As both Xavier and the keys are moving in same diretion. The relative speed wrt ground is given by :
V = v+v'
V= 14 + 8
V = 22 km/h
So, the speed of the keys relative to the ground is 22 km/h.
