PLEASE HELP ANYONE PLEASE HELP !!!!

A semicircular archway is built in front of a garden using 8 congruent granite tiles, as shown in the diagram. Find the area of

crimeas [40]

So there's 8 tiles.
Radius from archway to the outer edge would be : 7 +1 = 8ft

You can use this formula to count the area of semi circle : π r^2/2

A = 3.14 x 8ft^2 = 100.48 ft ^2
A = 3.14 x 7ft^2= 76.92 ft^2

100.48 - 76.92 = 23.55 ft^2

Then you have to divide it with the total tiles
23.55/8 = 2.94 ft^2 per tile >> (rounded to nearest tenth)

hope this helps

5 0

3 years ago

Which term describes the slope of the line below?

saul85 [17]

Answer:

negative

Step-by-step explanation:

looking at the slope of the straight line, a positive slope will begin on the 1st quadrant and end at the 3rd quadrant

meaning if the slope is negative, it will begin on the 2nd quadrant and end on the 4th quadrant

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to cot t sec t?

Solnce55 [7]

Answer: $csc(t)$

Step-by-step explanation:

Alright, lets get started.

The given expression is given as :

$cot( t) \times sec (t)$

We know quotient identity as :

$cot(t)=\frac{cos(t)}{sin(t)}$

Similarly, we know reciprocal identity as :

$sec(t)=\frac{1}{cos(t)}$

lets plug the value of cot and sec in given expression

$\frac{cos(t)}{sin(t)} \times \frac{1}{cos(t)}$

cos will be cancelled, remaining will be

$\frac{1}{sin(t)}$

Using reciprocal identity again, that will equal to :

$csc(t)$ ................... Answer (A)

8 0

3 years ago

(15 points please help)

dsp73

C. You can graph it on Desmos and all the given points work.

5 0

3 years ago

Read 2 more answers

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago