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Zepler [3.9K]
3 years ago
10

PLEASE HELP ANYONE PLEASE HELP !!!!

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0
The answer to the question 7 is the last one 
aliya0001 [1]3 years ago
4 0
1. Square

2. (0, 0), (6,3) (6,13),(-0.5,0)
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A semicircular archway is built in front of a garden using 8 congruent granite tiles, as shown in the diagram. Find the area of
crimeas [40]
So there's 8 tiles.
Radius from archway to the outer edge would be : 7 +1 = 8ft

You can use this formula to count the area of semi circle : π r^2/2

A = 3.14 x 8ft^2 = 100.48 ft ^2
A = 3.14 x 7ft^2=  76.92  ft^2

100.48 - 76.92 = 23.55 ft^2

Then you have to divide it with the total tiles 
23.55/8 = 2.94 ft^2 per tile >> (rounded to nearest tenth)

hope this helps
5 0
3 years ago
Which term describes the slope of the line below?
saul85 [17]

Answer:

negative

Step-by-step explanation:

looking at the slope of the straight line, a positive slope will begin on the 1st quadrant and end at the 3rd quadrant

meaning if the slope is negative, it will begin on the 2nd quadrant and end on the 4th quadrant

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to cot t sec t?
Solnce55 [7]

Answer: csc(t)

Step-by-step explanation:

Alright, lets get started.

The given expression is given as :

cot( t) \times sec (t)

We know quotient identity as :

cot(t)=\frac{cos(t)}{sin(t)}

Similarly, we know reciprocal identity as :

sec(t)=\frac{1}{cos(t)}

lets plug the value of cot and sec in given expression

\frac{cos(t)}{sin(t)}  \times \frac{1}{cos(t)}

cos will be cancelled, remaining will be

\frac{1}{sin(t)}

Using reciprocal identity again, that will equal to :

csc(t)  ................... Answer (A)

8 0
3 years ago
(15 points please help)
dsp73
C. You can graph it on Desmos and all the given points work. 
5 0
3 years ago
Read 2 more answers
Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0
3 years ago
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