The question was not well arranged above. It has been arranged in the answer below.
Question:
Leon made a study chart about human-induced changes to the environment.
Environmental Changes Caused by Humans
X Y
Results from introducing harmful substances into the environment
Example: oil spill
Results from natural areas being cleared and replaced by human development
Example: deforestation
Which headings best complete the chart?
X: Habitat Destruction
Y: Pollution
X: Long-Term Changes
Y: Short-Term Changes
X: Short-Term Changes
Y: Long-Term Changes
X: Pollution
Y: Habitat Destruction
Answer:
X: Pollution
Y: Habitat Destruction
Explanation:
From the above question, Leon gave us two variables, X and Y.
The human induced changes were divided into two.
1. Results from introducing harmful substances into the environment
Introducing harmful substances into the environment is also called pollution. And we can represent this as X which is the first variable.
2. Results from natural areas being cleared and replaced by human development.
This description given in number two above whereby land areas are been cleared and replaced by human development has a negative effects on the environment because the vegetation which includes the trees are been cut down and living organisms(animals) will go extinct gradually. This act affect the balance of the ecosystem and it can be referred to as the destruction of the habitat of living organisms
Therefore, the correct headings best complete the chart is :
X: Pollution
Y: Habitat Destruction
In accordance with Dalton's Law of multiple proportions
<h3>Further explanation</h3>
Given
6.0g of carbon
22.0g or 14.0g of product
Required
related laws
Solution
the amount of air present ⇒ as an excess or limiting reactant
- air(O₂) as a limiting reactant(product=14 g)
C+0.5O₂⇒CO
6 + 8 = 14 g
mol O₂=8 g : 32 g/mol=0.25
mol C = 6 g : 12 g/mol = 0.5(2 x mol O₂)
mol CO= 2 x mol O₂ = 0.5 mol = 0.5 x 28 g/mol = 14 g
- air(O₂) as an excess reactant(product=22 g) an C as a limiting reactant
C+O₂⇒CO₂
6 + 16 = 22 g
mol C = 6 g : 12 g/mol = 0.5
mol O₂ = 16 g : 32 g/mol=0.5
mol CO₂ = 22 g : 44 g/mol = 0.5
if the mass firs element (C) constant, then the mass of the second element(O) in the two compounds will have a ratio as a simple integer.
CO = 6 : 8
CO₂ = 6 : 16
the ratio O = 8 : 16 = 1 : 2
In accordance with Dalton's Law of multiple proportions
It is 300! hope this helps :)
Answer:
La reacción de etano, CH₃CH₃ y cloro, Cl₂ en presencia de luz solar se conoce como reacción de halogenación.
Los radicales de cloro se forman cuando el cloro se expone a la luz solar a continuación;
Cl₂ → 2Cl *
Se forma un radical etano cuando el etano, C₂H₆ reacciona con un radical libre de cloro, Cl *, como sigue;
C₂H₆ + Cl → C₂H₅ * + HCl
Se forma un producto halogenado cuando un radical libre de etano reacciona con una molécula de cloro como sigue;
C₂H₅ * + Cl₂ → C₂H₅Cl + Cl *
Un producto halogenado puede reaccionar además con un radical libre para producir como sigue;
C₂H₅Cl + Cl * → C₂H₅Cl₂
Explanation:
