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zheka24 [161]
3 years ago
13

How many Lewis dots does the cation [Ne 3+], (Neon with a +3 charge) have?

Chemistry
1 answer:
Ksju [112]3 years ago
4 0
The correct answer is B because 3 + 3 equals six
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Answer:

The relative atomic mass of chlorine depends on the ratio between the abundance of these two naturally-occurring isotopes.

Explanation:

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For these two naturally-occurring isotopes of chlorine:

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\begin{array}{|c|c|c|}\cline{1-3} \text{Isotope} & \text{Atomic Mass} & \text{Relative Abundance}\\ \cline{1-3} ^{35}{\rm Cl} & \approx 34.968\; \rm Da} & \approx 0.758 \\ \cline{1-3} ^{37}{\rm Cl} & \approx 36.966\; \rm Da & \approx 0.242 \\ \cline{1-3}\end{array}.

\begin{aligned}&\text{relative atomic mass of Cl} \\ &= \text{atomic mass of $^{35}{\rm Cl}$} \times \text{relative abundance of $^{35}{\rm Cl}$} \\&\quad + \text{atomic mass of $^{37}{\rm Cl}$} \times \text{relative abundance of $^{37}{\rm Cl}$} \\ &\approx 34.968\; \rm Da \times 0.758 + 36.966\; \rm Da \times 0.242 \\ &\approx 35.45\; \rm Da \end{aligned}.

The relative abundance of ^{35}{\rm Cl} is much higher than that of ^{37}{\rm Cl}. Consequently, the relative atomic mass of the element \rm Cl is closer to the atomic mass of ^{35}{\rm Cl}\! than that of ^{37}{\rm Cl}\!.

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