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Nataliya [291]
3 years ago
6

Sugar dissolves in warm water is a physical or chemical change

Chemistry
2 answers:
My name is Ann [436]3 years ago
7 0

It is a chemical change.

Inessa [10]3 years ago
7 0
Physical. they are not chemically combined, its a man made mixture.
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Look at the picture and select the answer quicly
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I believe c. I hope it helps :)
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3 years ago
Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .
melisa1 [442]

The value of ideal gas constant (R) in Joule is 8.314 Joule Kelvin^{-1}mol^{-1}. Now the given expression is 1.00 J. gg^{-1}.mole^{-1}. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin  = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C  = (-) \frac{8.314}{272.15}=0.030g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.  

7 0
4 years ago
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Tổng số hạt e, p, n của nguyên tử M là 40, số hạt mang điện hơn số hạt không mang điện
hodyreva [135]

Answer:

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Explanation:

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8 0
3 years ago
The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
SashulF [63]

ΔG° for the reaction is 5.47kJ mol⁻¹.

The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.

By using the formula;

ΔG° = −RTlnKp

Where,

R = 8.3Jk⁻¹mol⁻¹

T = Temperature = 427 + 273 = 700 K

Kp = 8×10⁻⁵(given)

Substituting the value, we get,

ΔG° = −8.3 × 700 × ln(23×10⁻⁵)

ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       =  - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       = − 8.3 × 700 × (2.07−11.5)

       =5.47×10⁴Jmol¹

       =5.47kJ mol⁻¹

Therefore,  ΔG° for the reaction is 5.47kJ mol⁻¹.

Learn more about Gibbs free energy here:

brainly.com/question/13765848

#SPJ4

7 0
2 years ago
How many moles of KCl will be formed from 2.73 grams of KClO3
Art [367]

Answer:

0.0222 mol KCl

Explanation:

2 KClO3 (s)   2 KCl (s) + 3 O2 (g)

2.73 g                x mol

x g KCl = 2.73 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]

x g KCl = 0.0222 mol KCl

8 0
3 years ago
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