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2 years ago

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Mathematics

1 answer:

Drupady [299]2 years ago

3 0

Answer: The answer is Yes. A square is a rectangle because it possesses all the properties of a rectangle. These properties are: Interior angles measure 90∘ each.

Explanation:

Definition of a Rectangle:

A 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also, opposite sides are parallel and of equal length.

Definition of a Square:

A 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also, all sides have equal length

As you can see the first part of the definition of a square and rectangle are the same.

However, a square is a special case of a rectangle.

When all 4 sides of a rectangle are equal then the rectangle is a square.

So, a rectangle can also sometimes be a square.

Step-by-step explanation:

You might be interested in

The diagram shows an isosceles right

Pachacha [2.7K]

Answer:1. 1.0 1.0 1.4

Step-by-step explanation:

5 0

2 years ago

Please help!!! which ones apply, there may be more than one answer~

dangina [55]

B. and c. is the answer

6 0

3 years ago

taurus [48]

Answer:

$x^2 - 2x + 10$ , option B

Step-by-step explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:

$i^2 = -1$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

The solutions are:

$x_1 = 1 - 3i, x_2 = 1 + 3i$

We have to find the polynomial. All option have $a = 1$ . So

$(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10$

The correct answer is given by option b.

6 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

nataly862011 [7]

Let (x, y, z) be a point on the plane in the first octant. The box formed by this point has volume xyz, and you want to maximize this subject to the equation of the plane.

Use the method of Lagrange multipliers: the Lagrangian is

L(x, y, z) = xyz - λ (x + 2y + 3z - 6)

Find its critical points:

∂L/∂x = yz - λ = 0

∂L/∂y = xz - 2λ = 0

∂L/∂z = xy - 3λ = 0

∂L/∂λ = -(x + 2y + 3z - 6) = 0

Solving the first three equations for λ gives

λ = yz = xz/2 = xy/3

Solve these equations for y and z :

• yz = xz/2 => y = x/2 => 2y = x

• yz = xy/3 => z = x/3 => 3z = x

Substitute these solutions into the last equation and solve for x, then again for y and z :

x + 2y + 3z - 6 = 3x - 6 = 0 => 3x = 6 => x = 2, y = 1, z = 2/3

At this critical point, the maximum volume is

xyz = 2*1*2/3 = 4/3

4 0

3 years ago

Which is the graph of x – y = 1?

Jet001 [13]

Answer:

its the second graph

Step-by-step explanation:

you could use this website to find out graph

desmos calculator

5 0

3 years ago