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frosja888 [35]
3 years ago
8

When 9 2/3 is written in simplest radical form, which value remains under the radical? 3 6 9 O 27​

Mathematics
2 answers:
Kamila [148]3 years ago
8 0
Answer: 6 (hope you do good :D)
MissTica3 years ago
7 0

Answer:

3

Step-by-step explanation:

A

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Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

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Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

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\implies \dfrac{1}{16}

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\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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