Question

A sheet of aluminum (Al) foil has a total area of 1.000 ft2 and a mass of 3.636 g. What is the thickness of the foil in millimeters (density of Al =2.699 g/cm^3)?

Answer 1

Answer:

The thickness of the foil is 0.01450 mm

Explanation:

1 ft = 30.48 cm

So area of Al foil is $(30.48)^{2}cm^{2}$

if thickness of foil is d cm then volume of Al foil is $(30.48)^{2}dcm^{3}$

We know, $density = \frac{mass}{volume}$

Here density of Al is 2.699 $g/cm^{3}$ and mass of foil is 3.636 g.

So volume of foil is $\frac{3.636 g}{2.699g/cm^{3}}$ or $\frac{3.636}{2.699}cm^{3}$

So, $(30.48)^{2}d=\frac{3.636}{2.699}$

or, d = 0.001450

So thickness of foil is 0.001450 cm or 0.01450 mm