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3 years ago

Which of the following is the electron configuration of an electrically neutral alkaline earth metal

Chemistry

1 answer:

podryga [215]3 years ago

5 0

Answer:

Option d, 1s2 2s2 2p6 3s2 3p6 4s2

Explanation:

Alkaline earth metals belong to group 2 of the periodic table. Elements belonging to group 2 are beryllium, magnesium, calcium, strontium and barium and radium.

Alkaline earth metals have 2 valence electrons and these two electrons are filled in outermost s sub shell.

General electronic configuration of alkaline earth metal: ns^2

In ionized state, number of electrons in s sub shell will not be 2.

Among the given, only 1s2 2s2 2p6 3s2 3p6 4s2, has 2 electrons in s sub shell. So, it an electronic configuration of neutral alkaline earth metal.

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Read 2 more answers

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3 years ago

For a first-order reaction, after 2.00 min, 20% of the reactants remain. Calculate the rate constant for the reaction. 1. 74.6 s

garri49 [273]

<u>Answer:</u> The rate constant for the reaction is $0.013412s^{-1}$

<u>Explanation:</u>

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = ?

t = time taken for decay process = 2.00 min = 120 seconds (Conversion factor: 1 min = 60 seconds)

$[A_o]$ = initial amount of the sample = 100 grams

[A] = amount left after decay process = 20 grams

Putting values in above equation, we get:

$k=\frac{2.303}{120}\log\frac{100}{20}\\\\k=0.013412s^{-1}$

Hence, the rate constant for the reaction is $0.013412s^{-1}$

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3 years ago