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3 years ago

Which of the following is the electron configuration of an electrically neutral alkaline earth metal

Chemistry

1 answer:

podryga [215]3 years ago

5 0

Answer:

Option d, 1s2 2s2 2p6 3s2 3p6 4s2

Explanation:

Alkaline earth metals belong to group 2 of the periodic table. Elements belonging to group 2 are beryllium, magnesium, calcium, strontium and barium and radium.

Alkaline earth metals have 2 valence electrons and these two electrons are filled in outermost s sub shell.

General electronic configuration of alkaline earth metal: ns^2

In ionized state, number of electrons in s sub shell will not be 2.

Among the given, only 1s2 2s2 2p6 3s2 3p6 4s2, has 2 electrons in s sub shell. So, it an electronic configuration of neutral alkaline earth metal.

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A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?

Katen [24]

V ( HCl ) = 16.4 mL / 1000 => 0.0164 L

M( HCl) = ?

V( KOH) = 12.7 mL / 1000 => 0.0127 L

M(KOH) = 0.620 M

Number of moles KOH:

n = M x V

n = 0.620 x 0.0127

n = 0.007874 moles of KOH

number of moles HCl :

HCl + KOH = H2O + KCl

1 mole HCl ------ 1 mole KOH
? mole HCl--------0.007874 moles KOH

moles HCl = 0.007874 * 1 / 1

= 0.007874 moles of HCl

M = n / V

M = 0.007874 / 0.0164

= 0.480 M

Answer (2)

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3 years ago

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scoundrel [369]

Answer:

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