The combustion reaction is as expressed,
CxHy + O2 --> CO2 + H2O
The mass fraction of carbon in CO2 is 3/11. Hence,
mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.
Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.
moles of C = 0.86 g C / 12 g = 0.0713
moles of H = 0.14 g H / 1 g = 0.14
The empirical formula for the hydrocarbon is therefore, CH₂.
Answer:
9.63 L.
Explanation:
Hello,
In this case, the undergoing chemical reaction is:

So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:

In such a way, the yielded moles of hydrobromic acid and chlorine are:

Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.
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If it is blue litmus paper, it will remain blue. If it is red litmus paper, it will remain red. Water is neither an acid nor a base so it will not change the litmus paper.
Answer:
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